, Rockville, MD 20857
Tel: 301-427-1564
-Original Message-
From: David Winsemius [mailto:dwinsem...@comcast.net]
Sent: Thursday, June 16, 2016 12:54 PM
To: Muhuri, Pradip (AHRQ/CFACT)
Cc: r-help@r-project.org
Subject: Re: [R] dplyr's arrange function - 3 solutions received - 1 Ne
quot;93.5 (0.90)" "52.7 (3.90)"
> ...
> $ ppv : chr "90.4 (0.94)" "92.8 (0.85)" "93.7 (0.87)" "94.3 (0.63)"
> ...
> $ npv : chr "61.5 (3.00)" "92.8 (2.27)" "96.9 (0.63)" "
t;92.8 (2.27)" "96.9 (0.63)" "87.5 (3.27)"
...
$ kappa : chr "0.536 (0.029)" "0.676 (0.032)" "0.905 (0.011)" "0.626
(0.035)" ...
Pradip K. Muhuri, AHRQ/CFACT
5600 Fishers Lane # 7N142A, Rockville, MD 20857
Tel: 301-427-156
> On Jun 15, 2016, at 2:08 PM, Muhuri, Pradip (AHRQ/CFACT)
> wrote:
>
> Hello,
>
> I am using the dplyr's arrange() function to sort one of the many data
> frames on a character variable (named "prevalence").
>
> Issue: I am not getting the desired output (line 7 is the problem, which
>
Hi Pradip,
I'll assume that you are reading the data from a file:
pm.df<-read.csv("pmdat.txt",stringsAsFactors=FALSE)
# create a vector of numeric values of prevalence
numprev<-as.numeric(sapply(strsplit(trimws(pm.df$prevalence)," "),"[",1))
# order the data frame by that vector
pm.df[order(numpre
On 6/15/2016 2:08 PM, Muhuri, Pradip (AHRQ/CFACT) wrote:
Hello,
I am using the dplyr's arrange() function to sort one of the many data frames on a
character variable (named "prevalence").
Issue: I am not getting the desired output (line 7 is the problem, which
should be the very last line
Hello,
I am using the dplyr's arrange() function to sort one of the many data frames
on a character variable (named "prevalence").
Issue: I am not getting the desired output (line 7 is the problem, which
should be the very last line in the sorted data frame) because the sorted field
is cha
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