Hi Medic,
Am 10.05.20 um 09:15 schrieb Medic:
I took a SAMPLE CODE (for Connected scatterplot) from the R gallery
and applied to MY DATA, but got:
"Don't know how to automatically pick scale for object ..."
P.S. 1) R ver. 4.0 (Yes, Jeff); 2) Attached: mydata_dput (1 КБ)
SAMPLE CODE
library(ggp
Many Thanks!!!
> cpolw...@chemo.org.uk:
> Your X axis is plotting mydata not date?
> Use aes(x=date
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I took a SAMPLE CODE (for Connected scatterplot) from the R gallery
and applied to MY DATA, but got:
"Don't know how to automatically pick scale for object ..."
P.S. 1) R ver. 4.0 (Yes, Jeff); 2) Attached: mydata_dput (1 КБ)
SAMPLE CODE
library(ggplot2)
library(dplyr)
library(hrbrthemes)
data <-
Am 10.05.20 um 04:17 schrieb Bert Gunter:
> $date is a factor, which is coded as numeric values internally, which
> as.date sees as numeric, and therefore:
> "as.Date will accept numeric data (the number of days since an epoch),
> but only if origin is supplied." (from ?as.Date)
as.Date is also ab
True. Whence the error message then?
Still, in my attempt to reproduce, the format statement worked.
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Sat, May 9,
... but str says it is character. This must be 4.0...
On May 9, 2020 7:17:16 PM PDT, Bert Gunter wrote:
>$date is a factor, which is coded as numeric values internally, which
>as.date sees as numeric, and therefore:
>"as.Date will accept numeric data (the number of days since an epoch),
>but only
$date is a factor, which is coded as numeric values internally, which
as.date sees as numeric, and therefore:
"as.Date will accept numeric data (the number of days since an epoch),
but only if origin is supplied." (from ?as.Date)
You need to supply a format argument to as.Date to get it to handle
I took a SAMPLE CODE (for Connected scatterplot) from the R gallery
and applied to MY DATA, but got:
"Error in as.Date.numeric(mydata$date) : 'origin' must be supplied".
P.S. I can not understand ?as.Date()
SAMPLE CODE
library(ggplot2)
library(dplyr)
library(hrbrthemes)
data <-
read.table("https:
Duncan
-Original Message-
From: Christine Lee [mailto:leptostra...@yahoo.com]
Sent: Wednesday, 19 August 2015 00:26
To: R; Duncan Mackay
Subject: RE: [R] date format in xyplot
Thank you Duncan,
I have tried the scales function. It ends up with 2015-09-15, which is
acceptable. It is far much
-
2015年8月18日 星期二，Duncan Mackay 寫道﹕
主題: RE: [R] date format in xyplot
收件人: "R"
日期: 2015年8月18日,星期二,下午4:08
Hi Christine
If somethings go wrong:
1 first check your data
str(Raw)
'data.frame': 10 obs. of
5 variables:
$ Date : F
Sorry, quick follow-up: is there any chance you used Date rather than Date1 in
the original plot?
John Kane
Kingston ON Canada
> -Original Message-
> From: r-help@r-project.org
> Sent: Mon, 17 Aug 2015 21:15:39 -0700
> To: r-help@r-project.org
> Subject: [R] date f
ho knows with R :)
John Kane
Kingston ON Canada
> -Original Message-
> From: r-help@r-project.org
> Sent: Mon, 17 Aug 2015 21:15:39 -0700
> To: r-help@r-project.org
> Subject: [R] date format in xyplot
>
> To whom it may concern,
>
> I have tried to plot some num
ing the parameters set by trellis.par.set() to the
function
to get them
names(trellis.par.get() )
and going further
trellis.par.get()$superpose.symbol
will give you the values for superpose.symbol
Beware: Do not make the labels etc so big that the axis labels are hard to
read. Think of final size
To whom it may concern,
I have tried to plot some numbers against time with the time on the X-axis
shown as "Jan", "Feb", etc.
I used the following commands:
Raw<-structure(list(Date = structure(c(6L, 7L, 2L, 4L, 12L, 9L, 7L,
2L, 4L, 12L), .Label = c("1/10", "1/11", "11/11", "12/11", "13/10",
#Or
paste(dat[,3],dat[,2],dat[,1],sep=".")
#[1] "4.1.2011" "5.2.2012" "6.3.2013"
#
as.character(interaction(dat[,3:1]))
paste(sprintf("%02d",dat[,3]),sprintf("%02d",dat[,2]),dat[,1],sep=".")
#[1] "04.01.2011" "05.02.2012" "06.03.2013"
A.K.
On Thursday, November 28, 2013 10:18 AM, Rui Bar
Hi,
Try:
dat1 <- data.frame(years=rep(1991:1992,12), months=rep(1:12,2),days= rep(1,24))
dat1$day <-
format(as.Date(paste(dat1[,1],sprintf("%02d",dat1[,2]),sprintf("%02d",dat1[,3]),sep="."),"%Y.%m.%d"),"%d.%m.%Y")
A.K.
On Thursday, November 28, 2013 8:56 AM, eliza botto
wrote:
Dear Users of
Thnx rui,
Eliza
> Date: Thu, 28 Nov 2013 15:16:35 +
> From: ruipbarra...@sapo.pt
> To: eliza_bo...@hotmail.com; r-help@r-project.org
> Subject: Re: [R] date format
>
> Hello,
>
> Maybe something like the following.
>
> dat <- data.frame( = 2011:2013, m
Hello,
Maybe something like the following.
dat <- data.frame( = 2011:2013, mm = 1:3, dd = 4:6)
apply(dat, 1, function(x) paste(rev(x), collapse = "."))
Hope this helps,
Rui Barradas
Em 28-11-2013 13:54, eliza botto escreveu:
Dear Users of R,
I have a data frame with three column, the f
Dear bert, arun and philipps,Thanks for your help. It worked perfectly fine for
me.:D
Eliza
> Date: Thu, 28 Nov 2013 16:09:58 +0100
> From: wev...@web.de
> To: eliza_bo...@hotmail.com; r-help@r-project.org
> Subject: Re: [R] date format
>
> Hi Eliza,
>
> # you can u
eliza botto hotmail.com> writes:
>
> Dear Users of R,
> I have a data frame with three column, the first column contains years,
the second one months and third one,
> the days (cbind( mm dd)). I want to combine them so that i have one
column with the date format as (dd.mm.).
> Is there a
Dear Users of R,
I have a data frame with three column, the first column contains years, the
second one months and third one, the days (cbind( mm dd)). I want to
combine them so that i have one column with the date format as (dd.mm.).
Is there a way of doing that.
Thanks in advance,
Eliza
Hi,
thanks A.K
try this not working
#*
# Load historical data
#**
library('quantmod')
endDate =Sys.Date()
startDate = as.Date(endDate-10, order="ymd")
dataspy = getSymbo
D'oh -- won't work in general (weekends!) -- serves me right for being
lazy on a Friday.
What your problem is that variables aren't extrapolated into strings,
so you'll need to construct the subset string directly:
dataspy[paste(startDate, endDate, sep="/")]
or some such. (Untested!)
Cheers,
Mi
head(dataspy, 6) seems easiest.
Cheers,
Michael
On Fri, Nov 2, 2012 at 6:41 PM, veepsirtt wrote:
> Hi R,
> How to get the range of values form startDate to lastDate as given below?.
>
> #*
> # Load historical data
> #***
#2012-10-05 146.91 147.16 145.70 146.14 124842100 146.14
#2012-10-08 145.60 146.12 145.31 145.64 78415400 145.64
A.K.
- Original Message -
From: veepsirtt
To: r-help@r-project.org
Cc:
Sent: Friday, November 2, 2012 2:41 PM
Subject: Re: [R] Date format co
Hi R,
How to get the range of values form startDate to lastDate as given below?.
#*
# Load historical data
#**
library('quantmod')
endDate =Sys.Date()
startDate = as.Dat
On Jun 28, 2011, at 8:04 AM, Ashim Kapoor wrote:
Dear R helpers,
I have 2 questions : -
1. My excel sheet has a column with dates like 01/03/1980 which is
formatted
as 03/80 when I read this into R it reads as Mar-80.
You should be able to change that from the format menu in Excel. If
You get the NA since it is indeterminate as to the date; paste on a 1
> for the day"
>
Alright Jim,
Many thanks.
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
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PLEASE d
You get the NA since it is indeterminate as to the date; paste on a 1
for the day"
> v<-c("Mar-80")
> as.Date(paste(v, '1'),format="%b-%y %d")
[1] "1980-03-01"
On Tue, Jun 28, 2011 at 8:04 AM, Ashim Kapoor wrote:
> Dear R helpers,
>
> I have 2 questions : -
>
> 1. My excel sheet has a column wi
Dear R helpers,
I have 2 questions : -
1. My excel sheet has a column with dates like 01/03/1980 which is formatted
as 03/80 when I read this into R it reads as Mar-80. How can I read it in
the source format ?
2.
> v<-c("Mar-80")
> as.Date(v,format="%b-%y")
[1] NA
>
Could someone please tell m
A reproducible example would help. What is "Phenology_VE$Date"? This works
> as.Date("2009-09-01", "%Y-%m-%d")
[1] "2009-09-01"
Is this the date you wanted:
> as.Date(39936, origin='1900-2-1')
[1] "2009-06-05"
On Wed, Sep 2, 2009 at 2:09 AM, swertie wrote:
>
> As suggested in the article R
As suggested in the article R News 4/1, I used
as.Date(as.character(Phenology_VE$Date), "%Y-%m-%d"), however this function
returns me only "NA" values
as.Date(as.character(Phenology_VE$Date), "%Y-%m-%d")
[1] NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA
NA
[26] NA NA NA
See R News 4/1. The article on dates there discusses how they
work and discusses Excel's dates as well.
On Tue, Sep 1, 2009 at 1:58 PM, swertie wrote:
>
> Hello, I plot the abundance of a species in relation to the date. To have the
> date as a continous variable I put it in the format "standard"
Behalf Of swertie
Sent: Tuesday, September 01, 2009 12:59 PM
To: r-help@r-project.org
Subject: [R] Date format in plot
Hello, I plot the abundance of a species in relation to the date. To
have the
date as a continous variable I put it in the format "standard" in
excel
(f.ex. 39939 means 06
On Sep 1, 2009, at 1:58 PM, swertie wrote:
Hello, I plot the abundance of a species in relation to the date. To
have the
date as a continous variable I put it in the format "standard" in
excel
(f.ex. 39939 means 06.05.2009). R uses 39939 on the x axis, but I
would like
to have "06.05". I
..@r-project.org] On
Behalf Of swertie
Sent: Tuesday, September 01, 2009 12:59 PM
To: r-help@r-project.org
Subject: [R] Date format in plot
Hello, I plot the abundance of a species in relation to the date. To have the
date as a continous variable I put it in the format "standard" in ex
Hello, I plot the abundance of a species in relation to the date. To have the
date as a continous variable I put it in the format "standard" in excel
(f.ex. 39939 means 06.05.2009). R uses 39939 on the x axis, but I would like
to have "06.05". I tried to use as.Date as suggested in some discussion
Hello Ben,
First of all thanks for the reply,and sorry because I haven't replied early.
In this time I find another form to create the "my time", like this:
bbrass = scan("C:/Program Files/R/data
PTIN/bbrass_client_2471_pool_72644_percent_in_use_500_NA.dat")
regts.start = ISOdatetime(2006, 7, 1,
Joao Santos-7 wrote:
>
> Hello,
>
> I problem is in the format of the date, my time series is like this:
>
> [snip]
>
> When I attempt to format the time like this:
>
> A <- read.table("file", sep="\t", col.names=c("date", "my1", "my2",
> "my3"))
> temp <- as.Date(A$date, format="%Y%m%d%H")
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