Yes! mapply is awesome! Thanks.
Gabor Csardi wrote:
>
> cumsum( mapply(function(i,j) sum(a$data[i:j]), x, y) )
>
> Is this what you want?
> Gabor
>
> On Thu, Mar 13, 2008 at 06:02:13AM -0700, yoo wrote:
>>
>> Hi all, i have the following..
>>
>> a <- data.frame(data = seq(1,10))
>>
>
In this case you can simply do
cumsum(a[x,]+a[y,])
Julian
yoo wrote:
> Hi all, i have the following..
>
> a <- data.frame(data = seq(1,10))
>
> i have indices:
> x <- c(1, 5, 3, 9)
> y <- c(2, 7, 4, 10)
>
> I want the cumsum of a[1:2], a[5:7], a[3:4]...
>
> is there an elegant way to
cumsum( mapply(function(i,j) sum(a$data[i:j]), x, y) )
Is this what you want?
Gabor
On Thu, Mar 13, 2008 at 06:02:13AM -0700, yoo wrote:
>
> Hi all, i have the following..
>
> a <- data.frame(data = seq(1,10))
>
> i have indices:
> x <- c(1, 5, 3, 9)
> y <- c(2, 7, 4, 10)
>
> I want the
Hi all, i have the following..
a <- data.frame(data = seq(1,10))
i have indices:
x <- c(1, 5, 3, 9)
y <- c(2, 7, 4, 10)
I want the cumsum of a[1:2], a[5:7], a[3:4]...
is there an elegant way to do it without any loop? Thanks!
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