Re: [R] creating a list based on various mean values

Does the following not do what you want? k1 <- c(0.005, 0.200, 0.300, 0.400, 0.500, 0.600, 0.700, 0.800, 0.900, 1.000, 1.100, 1.200, 1.300, 1.400, 1.500, 1.600, 1.700, 1.800, 1.900, 2.000, 5.000, 10.000) k1 xr <- lapply(k1, rnorm, n=20) xr On Fri, Oct 23, 2015 at 1:51 AM, Erin H

[R] creating a list based on various mean values

Hello! I would like to create a list of random values, based on various means. Here are the potential mean values: > k1 [1] 0.005 0.200 0.300 0.400 0.500 0.600 0.700 0.800 0.900 1.000 1.100 1.200 1.300 1.400 [15] 1.500 1.600 1.700 1.800 1.900 2.000 5.000 10.000 There are 22