HI, Dennis,
Thanks for the helps! All roads to Rome, appreciated!
On Thu, Sep 22, 2011 at 2:54 PM, Dennis Murphy wrote:
> Hi:
>
> Here's one approach with package reshape2. I copied the same data
> frame 10 times to illustrate the idea, but as long as your data frames
> have the same structur
Hi:
Here's one approach with package reshape2. I copied the same data
frame 10 times to illustrate the idea, but as long as your data frames
have the same structure (same variables, same dimension), this should
work.
library('plyr')
library('reshape2')
# Use your example data as the template:
ds
On Sep 22, 2011, at 2:06 PM, Changbin Du wrote:
HI, Michael,
The following codes are great!
first.out <- do.call("cbind", list(first, result.fun))
Would this have been easier?
> dat[ , c(1:3, rep(4, 5))]
probe_name chr_id position array1 array1.1 array1.2 array1.3
1C-7SARK 1 8
HI, Michael,
The following codes are great!
first.out <- do.call("cbind", list(first, result.fun))
colnames(first.out) <- c(colnames(first), paste("array",
seq(length(result.fun)), sep=""))
> head(first.out)
probe_name chr_id position array1 array2 array3 array4 array5 array6
array7
1C-7S
Thank, Jean, appreciated your help!
On Thu, Sep 22, 2011 at 10:52 AM, Jean-Christophe BOUËTTÉ <
jcboue...@gmail.com> wrote:
> Hi,
> It's hard to provide you with working code when you don't provide a
> reproducible example, but do you really need to create variables? What
> about (untested):
>
>
Thanks so much, Michael!
head(first)
probe_name chr_id position array1
1C-7SARK 1 849467 10
2C-4WYLN 1 854278 10
3C-3BFNY 1 854471 10
4C-7ONNE 1 874460 10
5C-6HYCN 1 874571 10
6C-7SCGC 1 874609 10
for( i i
On how to use named vs. positional arguments, you can also have a look
at section 2.3 of "an introduction to R".
2011/9/22 Jean-Christophe BOUËTTÉ :
> Hi,
> It's hard to provide you with working code when you don't provide a
> reproducible example, but do you really need to create variables? What
Hi,
It's hard to provide you with working code when you don't provide a
reproducible example, but do you really need to create variables? What
about (untested):
for (i in 1:2) {
first <-cbind(first, result.fun[[i]])
}
you will then have to look at
names(first)
and change the last part of it to
Actually, I think you can make that even easier:
first.out <- cbind(first, result.fun)
Michael Weylandt
On Thu, Sep 22, 2011 at 1:37 PM, R. Michael Weylandt <
michael.weyla...@gmail.com> wrote:
> There are a few ways to proceed from here. If you are really committed to
> this loop + assign idea
There are a few ways to proceed from here. If you are really committed to
this loop + assign idea, I'd provide the following code:
for( i in 2:3) {
label <- paste("array", i, sep="")
assign(label, value = result.fun[[i-1]] )
first <- cbind(first, get(label))
}
However, this is general
HI, Michael,
I tried use x and got the following:
> for (i in 2:3) {
+
+ assign(x=paste("array", i, sep=""), value=result.fun[[i-1]])
+
+ first <-cbind(first, x)
+
+ }
*Error in cbind(first, x) : object 'x' not found
*
But I checked the
ls()
"array2" "array3"were created.
Can I
There is no "lab=" argument for assign() hence the error. Did someone
provide you with example code that suggested such a thing? remove lab=
entirely or replace it with x= to make your code work. More generally type
?assign or args(assign) to see what the arguments for a function are.
More general
HI, Dear R community,
I am trying to created new variables and put into a data frame through a
loop.
My original data set:
head(first)
probe_name chr_id position array1
1C-7SARK 1 849467 10
2C-4WYLN 1 854278 10
3C-3BFNY 1 854471 10
4C-7ONNE
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