no need for a for loop - we can vectorize this:
> dt <- data.frame(a = c(1, 2, 3), b = c(3, 2, 2), c = c(1, 3, 5))
> dt
a b c
1 1 3 1
2 2 2 3
3 3 2 5
> dt[,paste("test", 1:2, sep="")] = rep(1:2, each=3)
> dt
a b c test1 test2
1 1 3 1 1 2
2 2 2 3 1 2
3 3 2 5 1 2
on 06
Hi,
Fortunately, I found a way.
--
> dt <- data.frame(a = c(1, 2, 3), b = c(3, 2, 2), c = c(1, 3, 5))
>
> for(i in 1:2){
>dt[, paste("test", i, sep = "")] <- rep(i, 3)
> }
-
Thanks.
Best,
Dong-hyun Oh
On Jun 26, 2008, at 6:34 PM, Jorge Ivan Velez
Dear Dong-hyun,
What about
dt <- data.frame(a = c(1, 2, 3), b = c(3, 2, 2), c = c(1, 3, 5))
test=matrix(rep(c(1,2),each=3),ncol=2)
colnames(test)=paste('test',1:2,sep="")
cbind(dt,test)
?
HTH,
Jorge
On Thu, Jun 26, 2008 at 12:23 PM, Dong-hyun Oh <[EMAIL PROTECTED]> wrote:
> Dear UseRs,
>
> I
Is this what you want
> dt <- data.frame(a = c(1, 2, 3), b = c(3, 2, 2), c = c(1, 3, 5))
> for (i in 1:2){
+ dt[[paste('test',i,sep="")]] <- rep(i,3)
+ }
> dt
a b c test1 test2
1 1 3 1 1 2
2 2 2 3 1 2
3 3 2 5 1 2
>
On Thu, Jun 26, 2008 at 12:23 PM, Dong-hyun Oh <[EM
Dear UseRs,
I would like to know the way to create a new column by naming it
simultaneously.
For example, in for() loop I want to create columns named as
paste("test", i, sep = ""), as shown below.
dt <- data.frame(a = c(1, 2, 3), b = c(3, 2, 2), c = c(1, 3, 5))
5 matches
Mail list logo
