Re: [R] create dataframe using structure ()

2014-05-11 Thread Luigi Marongiu
Dear all, there was indeed a misplaced parenthesis, so the last line runs as: .Names = c("row", "stimulation", "positivity", "group", "copy")), row.names = c(NA, -120L), class = "data.frame") with two )) at the end of .Names. problem solved, thank you Luigi On Thu, Mar 13, 2014 at 7:29 PM,

Re: [R] create dataframe using structure ()

2014-05-10 Thread William Dunlap
And I misplaced the closing parenthesis in my reponse - it goes before the .Names attribute as well. Bill Dunlap TIBCO Software wdunlap tibco.com On Sat, May 10, 2014 at 11:36 AM, William Dunlap wrote: > You made the same error as the first time - a misplaced parenthesis. > Make the last 2 lines

Re: [R] create dataframe using structure ()

2014-05-10 Thread William Dunlap
You made the same error as the first time - a misplaced parenthesis. Make the last 2 lines .Names = c("row", "stimulation", "positivity", "group", "copy")), row.names=c(NA, 120L), class="data.frame") instead of .Names = c("row", "stimulation", "positivity", "group", "copy"), row.names =

Re: [R] create dataframe using structure ()

2014-05-10 Thread arun
Hi, --- 2767.493803,4796.33016,12292.93705,3864.657567,9380.673835,14886.44683,8457.88646,26050.47191))),#   .Names = c("row", "stimulation", "positivity", "group", "copy"), row.names = c(NA, -120L),  class = "data.frame")  str(my.data) 'data.fram

Re: [R] create dataframe using structure ()

2014-05-10 Thread Luigi Marongiu
Hello, I have tried to apply this approach -- which worked for this example -- to a larger dataset. Although I have not received error messages, the variable I have set (my.data) is empty. Do you have any tip about this? Many thanks Luigi # code:: my.data<-structure(list( column_1 = 1:120, col

Re: [R] create dataframe using structure ()

2014-03-13 Thread arun
Hi, Try:  my.data <- structure(list(column_1 = 1:32, column_2 = structure(c(1, 2, 3, 4, 5, 6, 7, 8, 1, 2, 3, 4, 5, 6, 7, 8, 1, 2, 3, 4, 5, 6, 7, 8, 1, 2, 3, 4, 5, 6, 7, 8), .Label = c("Unstimulated", "ESAT6", "CFP10", "Rv3615c", "Rv2654", "Rv3879", "Rv3873", "PHA"), class = "factor"), column_3= s

Re: [R] create dataframe using structure ()

2014-03-13 Thread Rui Barradas
Hello, You're misplacing one close parenthesis. See the commented lines below. structure(list( column_1 = 1:32, column_2 = structure(c(1, 2, 3, 4, 5, 6, 7, 8, 1, 2, 3, 4, 5, 6, 7, 8, 1, 2, 3, 4, 5, 6, 7, 8, 1, 2, 3, 4, 5, 6, 7, 8), .Label = c("Unstimulated", "ESAT6", "CFP10", "Rv3615c", "Rv2654

Re: [R] create dataframe using structure ()

2014-03-13 Thread William Dunlap
Bill Dunlap TIBCO Software wdunlap tibco.com > -Original Message- > From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On > Behalf > Of Luigi Marongiu > Sent: Thursday, March 13, 2014 11:59 AM > To: r-help@r-project.org > Subject: [R] create d

[R] create dataframe using structure ()

2014-03-13 Thread Luigi Marongiu
dear all, I have tried to create a dataframe using the structure() function, but it did not really work. In column 1 i have the row number, in column 2 and 3 factors (8 and 4 levels respectively) and in column 4 the actual data. any clue on what went wrong? best regards luigi my.data<-structure(li