Try using aggregate( )
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On Mar 29, 2010, at 6:52 PM, Ali Tofigh wrote:
Assume you have a vector of characters x:
x
[1] "a" "b" "a" "d" "d" "c"
I use a function that counts the number of times each string occurs
in x:
sapply(unique(x), function(s) {sum(x == s)})
a b d c
2 1 2 1
Is there a more efficient way
Assume you have a vector of characters x:
> x
[1] "a" "b" "a" "d" "d" "c"
I use a function that counts the number of times each string occurs in x:
> sapply(unique(x), function(s) {sum(x == s)})
a b d c
2 1 2 1
Is there a more efficient way of doing this?
Cheers,
/Ali
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