Here are a couple of approaches:
> dftest<-data.frame(x=1:12, y=(1:12)%%4, z=(1:12)%%2)
> x_test=c("x","y")
> aggregate( dftest[,x_test], dftest['z'], FUN=mean )
z x y
1 0 7 1
2 1 6 2
>
> ### Or
>
> tmp.f <- as.formula( paste( 'cbind(',
+ paste( x_test, collapse=',' ),
+ ') ~ z' ) )
> aggregat
y
#1 0 7 1
#2 1 6 2
A.K.
- Original Message -
From: Blaser Nello
To: arun ; jpm miao
Cc: R help
Sent: Thursday, May 23, 2013 3:29 AM
Subject: RE: [R] convert a character string to a name
If you want to use the character string:
attach(dftest)
aggregate(cbind(sapply(x_test, get))~z,
try this:
> dftest<-data.frame(x=1:12, y=(1:12)%%4, z=(1:12)%%2)
> aggregate(cbind(x,y)~z, data=dftest, FUN=mean)
z x y
1 0 7 1
2 1 6 2
> x_test=c("x","y")
> a <- formula(paste0('cbind('
+ , x_test[1]
+ , ','
+ , x_test[2]
+
-help-boun...@r-project.org] On
Behalf Of arun
Sent: Donnerstag, 23. Mai 2013 09:19
To: jpm miao
Cc: R help
Subject: Re: [R] convert a character string to a name
with(dftest,aggregate(cbind(x,y),list(z),FUN=mean))
# Group.1 x y
#1 0 7 1
#2 1 6 2
#or
library(plyr)
ddply(dftest,.(z
: [R] convert a character string to a name
Hi,
From time to time I need to do the aggregation. To illustrate, I present
a toy example as below. In this example, the task is to aggregate x and y
by z with the function mean.
Could I call the aggregation function with x_test, where
x_test=c(&q
Hi,
From time to time I need to do the aggregation. To illustrate, I present
a toy example as below. In this example, the task is to aggregate x and y
by z with the function mean.
Could I call the aggregation function with x_test, where
x_test=c("x","y")? Thanks
Miao
> dftest<-data.fram
6 matches
Mail list logo
