Hello,
Try the following.
m <- unlist(months)
v <- unlist(values)
aggregate(v ~ m, FUN=sum)
tapply(v, m, sum)
Hope this helps,
Rui Barradas
Em 26-07-2012 18:49, jcrosbie escreveu:
I have two data frames. One with a matrix of months and the other with a
matrix of values. The two dataframes c
The values need not be a data frame as the number of unique months
could be different among the columns, right?. So you're going to have
to rethink your data structure. Probably as a list.
Once you get that straight,?tapply and friends should make it trivial,
if I understand you correctly.
-- Ber
I have two data frames. One with a matrix of months and the other with a
matrix of values. The two dataframes correspond to each other. I would like
to sum up all the values in by month.
What would be an efficient way to do this?
a=C(2,3,5,2,3,5)
b=c(2,6,3,2,6,3)
c=c(2,6,7,2,6,5)
months <- dat
3 matches
Mail list logo
