t;> > }}
>> > chi2(df1, alp=0.5, del=0.05)$Disc.data
>> >
>> > The point is that, observing the dataframe printed out by the last
>> > instruction, you can see that no attribute is removed. The
>discretized
>> data
>> > frame still h
r: "R-help" Date: Wed, 23 Nov 2016 22:26:45
To: peter dalgaard
Cc:
Subject: Re: [R] Chi2 algorithm - R
What does it mean to "have a mantainer"? Is he a third party? Is he an
individual developer and you can install whose package on your risk? Are
the package created by main
f(i %% 2 != 0){
> >df1 <- rbind(df1, iris[i,])
> >}}
> > chi2(df1, alp=0.5, del=0.05)$Disc.data
> >
> > The point is that, observing the dataframe printed out by the last
> > instruction, you can see that no attribute is removed. The discretized
>
e is removed. The discretized data
> frame still have 4 attributes discretized: if I correctly understood the
> above papers, Sepal Length and Sepal Width should have been both
> discretized in just one interval by Chi2 algorithm.
>
> I have posted a question here: http://stats.stackexcha
ave posted a question here: http://stats.stackexchange.com/questions/
247499/why-does-not-r-chi2-algorithm-discretize-in-the-
same-manner-as-in-the-paper-by-l?noredirect=1#comment470974_247499.
Moreover, it's really hard to understand the cut points that Chi2 algorithm
implemented in R makes. For example:
r
On 10-Oct-07 10:59:43, elyakhlifi mustapha wrote:
> Hello,
> I want to use the quantile function so I read the doc but I don't
> understand with this
>
>> qchisq(seq(0.05,0.95,by=0.05),df=(length(don)-1))
> [1] 62667.11 62795.62 62882.42 62951.47 63010.74 63064.00 63113.39
> 63160.27 63205.65 632
Oops... Check...
http://en.wikipedia.org/wiki/Chi-square_distribution
The Chi-square distribution for _any_ df has
mean = df and variance = 2df, so for large df, it's
approximately a normal distribution with mean = df and
sd = sqrt(2 df) [and not sqrt(df) as I wrote in a previous
message that, pr
Elyakhlifi Mustapha wrote:
>
> I want to use the quantile function so I read the doc but I don't
> understand with this
>
> > qchisq(seq(0.05,0.95,by=0.05),df=(length(don)-1))
> [1] 62667.11 62795.62 62882.42 62951.47 63010.74 63064.00 63113.39
> 63160.27 63205.65 63250.33 63295.04 63340.48 63
elyakhlifi mustapha wrote:
> Hello,
> I want to use the quantile function so I read the doc but I don't understand
> with this
>
>
>> qchisq(seq(0.05,0.95,by=0.05),df=(length(don)-1))
>>
> [1] 62667.11 62795.62 62882.42 62951.47 63010.74 63064.00 63113.39 63160.27
> 63205.65 63250.33 632
elyakhlifi mustapha wrote:
>
> Hello,
> I want to use the quantile function so I read the doc but I don't
> understand with this
>
>> qchisq(seq(0.05,0.95,by=0.05),df=(length(don)-1))
> [1] 62667.11 62795.62 62882.42 62951.47 63010.74 63064.00 63113.39
> 63160.27 63205.65 63250.33 63295.04 63
Hello,
I want to use the quantile function so I read the doc but I don't understand
with this
> qchisq(seq(0.05,0.95,by=0.05),df=(length(don)-1))
[1] 62667.11 62795.62 62882.42 62951.47 63010.74 63064.00 63113.39 63160.27
63205.65 63250.33 63295.04 63340.48 63387.48 63437.03 63490.53 63550.14 6
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