4
> 2 1 4 5 1
>
> Results should be OK although its structure is different, performance is
> not tested.
>
> Cheers
> Petr
>
> > -Original Message-
> > From: R-help On Behalf Of David McPearson
> > Sent: Friday, April 17, 2020 7:50 AM
> >
etr
> -Original Message-
> From: R-help On Behalf Of David McPearson
> Sent: Friday, April 17, 2020 7:50 AM
> To: r-help@r-project.org
> Cc: dc...@telstra.com
> Subject: Re: [R] calculate row median of every three columns for a dataframe
>
> Anna wrote:
> >
> > Hi al
Anna wrote:
Hi all,
I need to calculate a row median for every three columns of a
dataframe. I made it work using the following script, but not happy
with the script. Is there a simpler way for doing this?
To which Jim L responded:
Hi Anna,
I can't think of a simple way, but this fun
Inline.
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Thu, Apr 16, 2020 at 5:28 PM Jim Lemon wrote:
> Hi Anna,
> I can't think of a simple way, but this fun
Hi Anna,
I can't think of a simple way, but this function may make you happier:
step_median<-function(x,window) {
x<-unlist(x)
stop<-length(x)-window+1
xout<-NA
nindx<-1
for(i in seq(1,stop,by=window)) {
xout[nindx]<-do.call("median",list(x[i:(i+window-1)]))
nindx<-nindx+1
}
return(xout
You have *not* calculated row medians for all combinations of (is that
what you meant?) 3 columns of your data frame.
?combn with column indexing can help you do that. If that is not what
you meant, then ??
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and s
Hi all,
I need to calculate a row median for every three columns of a dataframe. I
made it work using the following script, but not happy with the script. Is
there a simpler way for doing this?
df = data.frame("a"=c(2,3,4),
"b"=c(3,5,1),"c"=c(1,3,6),"d"=c(7,2,1),"e"=c(2,5,3),"f"=c(4,5,1))tmed
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