Re: [R] basic hist() question

thanks, I'am not veru used with R!! regards 2010/8/21 Henrique Dallazuanna > Adel, > > read.table return a data.frame, Gavin showed, you need pass which column > will be plotted to hist. > scan return a vector. > > > On Sat, Aug 21, 2010 at 10:59 AM, Adel ESSAFI wrote: > >> It works fine. >> >

Re: [R] basic hist() question

Try this: a <- scan('dureetasks.txt') hist(a) On Sat, Aug 21, 2010 at 10:32 AM, Adel ESSAFI wrote: > Hi > In fact, I searching for a simpler solution. I remember that I have done > this without these functions (but I forgot) > simply, is there any function that "force" R to take variable a as

Re: [R] basic hist() question

Hi In fact, I searching for a simpler solution. I remember that I have done this without these functions (but I forgot) simply, is there any function that "force" R to take variable a as table ? Regards Adel > a=read.table("dureetasks.txt") > summary(a) V1 Min. : 1 1st Qu.:

Re: [R] basic hist() question

On Sat, 2010-08-21 at 11:37 +0200, Adel ESSAFI wrote: > Hi list > > I loaded the content of a file dureetasks.txt to variable a. This file > contains an interger per line. > when I print a vector, it displays correctly. > however, when I try to print the histogram, I get this error message > >

[R] basic hist() question

Hi list I loaded the content of a file dureetasks.txt to variable a. This file contains an interger per line. when I print a vector, it displays correctly. however, when I try to print the histogram, I get this error message > a=read.table("dureetasks.txt") > hist(a) Error in hist.default(a) :