not homework, but thanks for the hint!
Andras
On Sunday, October 27, 2013 7:51 AM, Patrick Burns
wrote:
Homework? A hint is:
?diff
Pat
On 27/10/2013 11:37, Andras Farkas wrote:
> Dear All,
>
> please help with the following problem:
>
> I have
>
>
> t <-seq(0,24,by=6)
> a <-600
> g <-0
Homework? A hint is:
?diff
Pat
On 27/10/2013 11:37, Andras Farkas wrote:
Dear All,
please help with the following problem:
I have
t <-seq(0,24,by=6)
a <-600
g <-0.05
b <-a*exp(-g*t)
I would like to establish a vector called z (for example) based on b where the
results are calculated as
Dear All,
please help with the following problem:
I have
t <-seq(0,24,by=6)
a <-600
g <-0.05
b <-a*exp(-g*t)
I would like to establish a vector called z (for example) based on b where the
results are calculated as :
z <-c(a-b[1],b[1]-b[2],b[2]-b[3],b[3]-b[4],b[4]-b[5])
so the results are:
... or using the handy with()
with(x,paste(n,l,sep="_"))
Slightly greater clarity and robustness, perhaps...
-- Bert
On Tue, Aug 21, 2012 at 9:24 AM, R. Michael Weylandt
wrote:
> You don't need loops or apply with paste since it's vectorized:
>
> x <- data.frame(n = 1:5, l = letters[1:5], stri
You don't need loops or apply with paste since it's vectorized:
x <- data.frame(n = 1:5, l = letters[1:5], stringsAsFactors = FALSE)
paste(x[,1], x[,2], sep = "_")
Cheers,
Michael
On Tue, Aug 21, 2012 at 10:57 AM, Chet Seligman wrote:
> This works, where zz is a dataframe:
>
> for(i in 1:nrow(
What is wrong with utilizing the vectorized nature of paste?
zz[[1]] <- paste(zz[[1]],zz[[2]],sep="_")
---
Jeff NewmillerThe . . Go Live...
DCN:Basics: ##.#. ##.#. Liv
This works, where zz is a dataframe:
for(i in 1:nrow(zz)) {
zzz[i,1]<-paste(zz[i,1],zz[i,2],sep="_")
}
I would like to use "apply" to concatentate two columns of text along with
a separator.
How?
Chet
[[alternative HTML version deleted]]
__
Hi clsnyder,
You forgot the MARGIN argument in you function call. Take a look at ?apply
apply(iris, 2, length)
apply(iris, 2, mean)
HTH,
Jorge
*
*
On Sat, Sep 17, 2011 at 6:42 PM, clsnyder <> wrote:
> Why does one method work, and the other not?
>
> attach(iris)
> head(iris)
>
> mean(Sepal.L
Why does one method work, and the other not?
attach(iris)
head(iris)
mean(Sepal.Length)
[1] 5.84
apply(iris, Sepal.Length, mean)
"Error in if (d2 == 0L) { : missing value where TRUE/FALSE needed"
I seem to get this error frequently with the apply functions but other
"manual" methods work no
Hi
r-help-boun...@r-project.org napsal dne 30.04.2010 23:11:54:
> Hello David,
>
> On Apr 30, 2010, at 11:00 PM, David Winsemius wrote:
> > Note: Loops may be just as fast or faster than apply calls.
> >
> How come!? is this true also for other similar functions: lapply, tapply
and sapply?
>
Hello David,
On Apr 30, 2010, at 11:00 PM, David Winsemius wrote:
> Note: Loops may be just as fast or faster than apply calls.
>
How come!? is this true also for other similar functions: lapply, tapply and
sapply?
Then the only advantage of these above is only syntactic sugar?
>>
>> indices
On Apr 30, 2010, at 4:52 PM, Giovanni Azua wrote:
Hello,
I have a bootstrap implementation loop that I would like to replace
by a faster "batch operator".
The loop is as follows:
for (b in 1:B) {
indices <- sample(1:N, size=N, replace=TRUE) # sample n elements
with replacement
theta_s
Hello,
I have a bootstrap implementation loop that I would like to replace by a faster
"batch operator".
The loop is as follows:
for (b in 1:B) {
indices <- sample(1:N, size=N, replace=TRUE) # sample n elements with
replacement
theta_star[b,] = statistic(data,indices) # exe
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