To answer my own question, the notes that I was drawing from made it seem as
through the mean I was using for my sum of squares was unweighted. In
reality, I needed to weight the contribution of each contributing mean by
the sample size. Once I did that, I got a value that agreed with SAS.
So, the
I sent a message a couple days ago about doing calculations for power of the
ANOVA. Several people got back to me very quickly which I really
appreciated.
I'm working now on a similar problem, but instead of a balanced ANOVA, I
have an unbalanced one. The first part of the question was:
You assum
2 matches
Mail list logo
