On Jun 19, 2012, at 5:36 PM, James Johnson wrote:
Hi All,
I have a microarray dataset as follows:
expt1 expt2 expt3 expt4 expt 5
gene1val val val val val
gene2val val val valval
.
.
..
gene15000
Hi All,
I have a microarray dataset as follows:
expt1 expt2 expt3 expt4 expt 5
gene1 val val val val val
gene2 val val val val val
.
.
..
gene15000 val val val val val
The re
Hi Dar.
It sounds like anova is a good way to go.
The command to look into in R is: ?aov
you might also go into manova (for anova for two dependent variables
together)
But make sure you understand the background of it when you work the
commands.
Cheers,
Tal
On Wed, Feb 25, 2009 at 11:06 PM,
Independent Variables: 5 different levels of exposure to information:
no information, appearance
information, educational information, contact information, and
personal information. The types Unranked Categorical Variable
Dependent Variables: 2 and are numerical
The dependent variable will be (2
Hi Dar.
could you please specify what type of variables the dependent and
independent variables are ? (numeric/ordered/categorical , what is their
range)
could you please specify how many dependent and independent variables you
have ? (numeric/ordered/categorical , what is their range)
In either
Subject
Re: [R] Anova Help?
Iâm just setting up the experiment and need help explaining what the
data analysis would be. Let me know of any questionsâ¦.. what would be
compared and how it would be measured. Is it a multi-way or 1-way
anova?
Thanks!
A 5 X 1 between-subject design will be
I’m just setting up the experiment and need help explaining what the
data analysis would be. Let me know of any questions….. what would be
compared and how it would be measured. Is it a multi-way or 1-way
anova?
Thanks!
A 5 X 1 between-subject design will be used for the experiment. Four
tool gr
Hi Dar.
I am not sure I got your question -
Are you asking what analysis to perform ?
Or how to perform it ?
Could you please give more details ?
On Wed, Feb 25, 2009 at 5:52 PM, Dar wrote:
> I am conducting an experiment where students are put into 5 total
> groups (one is the control grou
I am conducting an experiment where students are put into 5 total
groups (one is the control group). They are given a task and then I'm
measuring if there are differences (A 5 X 1 between-subject design
will be used for the experiment). I'm a little confused on the data
explanation (or should I s
p for something,
sometime
in your life." - Winston Churchill
From: Tal Galili [mailto:tal.gal...@gmail.com]
Sent: Sunday, February 15, 2009 10:25 AM
To: Joe King
Cc: r-help@r-project.org
Subject: Re: [R] anova help
Hi Joe,
you might want to have a look at the nlme package with the lm
25 AM
To: Joe King
Cc: r-help@r-project.org
Subject: Re: [R] anova help
Hi Joe,
you might want to have a look at the nlme package with the lme command.
Another option is the more advanced lmer package.
Lastly, you could have a look at the ?aov command, and notice the option of
using the +Er
Hi Joe,
you might want to have a look at the nlme package with the lme command.
Another option is the more advanced lmer package.
Lastly, you could have a look at the ?aov command, and notice the option of
using the +Error() term (but that would only work for balanced design cases,
so I've heard,
Provide some example data & code and someone may be able to help.
On Sat, Feb 14, 2009 at 2:46 PM, Joe King wrote:
> Hi all, I am trying to run a two factor anova, but one of the factors is a
> random factor, now I am also running in SPSS and it seems its dividing by
> the wrong term to get the a
Hi all, I am trying to run a two factor anova, but one of the factors is a
random factor, now I am also running in SPSS and it seems its dividing by
the wrong term to get the appropriate F term. here is my data. In SPSS the F
scores about double the ones in R, how can I specify one of my factors as
On Tue, 12 Aug 2008, Gareth Campbell wrote:
Hmm, I have my elements (as in chemical elements) as columns and my samples
as rows. This is the normal way round for all my other analyses. I think I
figured it out... I have 6 groups, all of about 10-12 samples and each with
31 elements. So for e
Hmm, I have my elements (as in chemical elements) as columns and my samples
as rows. This is the normal way round for all my other analyses. I think I
figured it out... I have 6 groups, all of about 10-12 samples and each with
31 elements. So for each group there are many more elements than sam
I've checked the function code and the error is returned form the following:
if (rss.qr$rank < ncol(resid))
stop(gettextf("residuals have rank %d < %d", rss.qr$rank, ncol(resid)),
domain=NA)
I read this as " If the Residual sums of squares $ rank ... " whatever that
is " is less than the numb
Thanks for that, the error I get when I use manova is this:
Error in summary.manova(fit) : residuals have rank 30 < 31
What does this mean??
When I call the formula I get 31 residuals and 31 residual standard errors.
Not sure why I get this error?
Thanks
Gareth
2008/8/11 S Ellison <[EMAIL PR
Hi,
I'm doing anova on a matrix of multivariate data where I want to assess the
effect of each column (element).
My matrix is 86 rows x 31 columns. I've created a grouping factor of length
86 containing group assignments of 6 types.
Then I run:
x<- aov(matrix~grouping.factor)
summary(aov.fit.r
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