Try pasting this into R (the first portion is from your post):
Lines <- "LST in mphDeg DegF DegF2%volts Deg
mph2 w/m2
050901 0.007.8 216.9 45.1 -999 24.4 -999 -999 10.60.2
0509010005 0.008.6 206.6 45.1 -999 25.2 -999 -999 11.7
Hi Gabor-
Your suggestion did work. However, maybe I should explain more what I
am trying to do. Once I have dataset (z) condensed to an hourly format
I will compare it with another dataset (lets call it y). Here's a
tidbit of dataset y:
doy yr mon day hr hgt1 hgt2 hgt3 co21 co22 co23 sig
Try this:
> aggregate(z$mph, trunc(time(z), "hour"), mean)
(09/01/05 00:00:00) (09/01/05 01:00:00) (09/01/05 02:00:00)
9.2750010.08333 9.2
On Tue, Dec 30, 2008 at 6:30 PM, Sherri Heck wrote:
> Dear All-
>
> I have a dataset that is comprised of the followi
Dear All-
I have a dataset that is comprised of the following (LST = yymmddhhMM):
LST in mphDeg DegF DegF2%volts Degmph2
w/m2
050901 0.007.8 216.9 45.1 -999 24.4 -999 -999
10.60.2
0509010005 0.008.6 206.6 45.1 -999 25.2
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