Hi
r-help-boun...@r-project.org napsal dne 01.06.2010 10:20:35:
> On 31/05/2010, Gabor Grothendieck wrote:
> > Use read.csv or read.table(..., sep = ","). Also note that if you
> > delete the first comma of the header (as in the second example below)
> > you won't have to specify row.names sinc
On 31/05/2010, Gabor Grothendieck wrote:
> Use read.csv or read.table(..., sep = ","). Also note that if you
> delete the first comma of the header (as in the second example below)
> you won't have to specify row.names since it can figure it out from
> the fact that there is one fewer column name
Hi,
Let's create your data.frame:
> dataframe <- structure(list(column1 = c(0.1, 0.3), column2 = c(0.2,
0.4)), .Names = c("column1",
"column2"), row.names = c("row1", "row2"), class = "data.frame")
> dataframe[,2]
[1] 0.2 0.4
> dataframe[,2, drop=FALSE]
column2
row1 0.2
row2 0.4
S
Use read.csv or read.table(..., sep = ","). Also note that if you
delete the first comma of the header (as in the second example below)
you won't have to specify row.names since it can figure it out from
the fact that there is one fewer column name than data fields.
> Lines <- ",column1,column2
+
Readers,
I have entered a file into r:
,column1,column2
row1,0.1,0.2
row2,0.3,0.4
using the command:
dataframe<-read.table("/path/to/file.csv",header=T,row.names=1)
When I try the command:
dataframe[,2]
I receive the response:
NULL
I was expecting:
row1 0.2
row2 0.4
What is my error with
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