Re: [R] Wild cards for dataframes

2021-10-22 Thread Bert Gunter
A terse but useful resource is to use R's Help docs: ?regex. It also gives the R regex syntax, which can of course differ from others, especially in regard to escapes. Do note that the rseek.org site is a better place to ask for such info than here. Or just searching on "regular expressions R". Be

Re: [R] Wild cards for dataframes

2021-10-22 Thread Grzegorz Smoliński
Well, Wikipedia is probably the place where people who know some topic can check if people who wrote the article did it right :) You can try this short subchapter in R for Data Science (by Hadley Wickham) as a starting point: https://r4ds.had.co.nz/strings.html#matching-patterns-with-regular-expr

Re: [R] Wild cards for dataframes

2021-10-22 Thread Eric Berger
You can check out Wikipedia for regular expressions: https://en.wikipedia.org/wiki/Regular_expression On Fri, Oct 22, 2021 at 3:48 PM Steven Yen wrote: > Thanks, it works! > > What can I read to understand more about this part "\\..*$" of the > pattern? And more such as ^ and $ that I know f

Re: [R] Wild cards for dataframes

2021-10-22 Thread Steven Yen
Thanks, it works! What can I read to understand more about this part "\\..*$" of the pattern? And more such as ^ and $ that I know from experience? On 2021/10/22 下午 06:22, Rui Barradas wrote: Hello, Use ls() with argument pattern. It accepts a regex and returns a vector of objects names mat

Re: [R] Wild cards for dataframes

2021-10-22 Thread Rui Barradas
Hello, Use ls() with argument pattern. It accepts a regex and returns a vector of objects names matching the pattern. rm(list = ls(pattern = "data\\..*$")) Hope this helps, Rui Barradas Às 10:20 de 22/10/21, Steven Yen escreveu: I like to be able to use a command with something similar to

[R] Wild cards for dataframes

2021-10-22 Thread Steven Yen
I like to be able to use a command with something similar to a "wild card". Below, lines 4 works to delete all three dataframes, but line 5 does not work. Any elegant way to accomplish this? My list of dataframes can be long and so this would be convenient. data.1<-data.frame(x=1:3,y=4:6,z=7:9