Yes thank you Jorge :working:
-
Anna Lippel
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Hi Anna,
Here is a suggestion:
# creating L1
L1 <- lapply(1:5, function(x) matrix(rnorm(10), ncol = 2))
L1
# creating L2
L2 <- lapply(1:5, function(x) sample(5, 2))
L2
# defining a function
foo <- function(x, y) list(x[-y,])
# result
mapply(foo, L1, L2)
HTH,
Jorge
On Fri, Mar 26, 2010 at 5:3
-5672
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of anna
Sent: Friday, March 26, 2010 5:35 PM
To: r-help@r-project.org
Subject: [R] Using lapply with two lists
Hello guys,
I have a list L1 of matrix. I have another list L2 with
Hello guys,
I have a list L1 of matrix. I have another list L2 with the same number of
elements representing the row of the L matrix that I want to delete
(L1[[i]][-L2[[i]],]) but I can't do this with lapply as it iterates through
L1 (first argument) and not L2. Any idea?
-
Anna Lippel
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