David,
Thanks for the response. I believe you have solved my problem.
Bob
On 7/26/2014 3:50 PM, David Winsemius wrote:
On Jul 26, 2014, at 11:07 AM, Robert Sherry wrote:
I have the following data set:
xy p
11 1/2
22 1/4
39 1/4
In this ca
On Jul 26, 2014, at 11:07 AM, Robert Sherry wrote:
I have the following data set:
xy p
11 1/2
22 1/4
39 1/4
In this case, p represents the probability of the values occurring. I
compute the covariance of x and y by hand and come up with a va
The Details section of ?cov.wt tells you that its divisor is not (n-1) for the
"unbiased" method. Or rather, it tells you what it does, and that that amounts
to dividing by n-1 _if_ the weights are equal.
(I never quite figured out under which sampling/weighting model this estimator
is actuall
I have the following data set:
xy p
11 1/2
22 1/4
39 1/4
In this case, p represents the probability of the values occurring. I
compute the covariance of x and y by hand and come up with a value of 41/16.
When computing the covariance, I am divi
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