n repeatedly. It moves to a new input variable
> when I call it back through a parameter
>
> repeat{
> function1(x)
> }
>
>
>
>
> -Original Message-
> From: Prof Brian Ripley [mailto:rip...@stats.ox.ac.uk]
> Sent: 07 December 2010 13:23
> To: Santosh
osh Srinivas
Cc: r-help@r-project.org
Subject: Re: [R] Time out for a R Function
On Tue, 7 Dec 2010, Santosh Srinivas wrote:
> Hello Group,
>
> I have an R-function that works fine for most part but sometime runs into
a
> long loop! (I'm lazy and short on time to debug right now so wa
> Date: Tue, 7 Dec 2010 16:11:42 +1100
> From: michael.bedw...@gmail.com
> To: santosh.srini...@gmail.com; r-help@r-project.org
> Subject: Re: [R] Time out for a R Function
>
> Below is a toy function with one way of doing it. There
On Tue, 7 Dec 2010, Santosh Srinivas wrote:
Hello Group,
I have an R-function that works fine for most part but sometime runs into a
long loop! (I'm lazy and short on time to debug right now so want to do
something easy)
For my purpose, it is ok to make few errors is there a way I can put
See also R help thread 'Wait for keystroke or timeout':
http://www.mail-archive.com/r-help@r-project.org/msg97742.html
/H
On Mon, Dec 6, 2010 at 9:11 PM, Michael Bedward
wrote:
> Below is a toy function with one way of doing it. There are bound to
> be better ways :)
>
> function(niter = 10, ti
Below is a toy function with one way of doing it. There are bound to
be better ways :)
function(niter = 10, time.out = 3) {
pretend.task <- function() {
Sys.sleep(0.5)
}
start <- proc.time()
for (iter in 1:niter) {
pretend.task()
cur <- proc.time() - start
if (c
Hello Group,
I have an R-function that works fine for most part but sometime runs into a
long loop! (I'm lazy and short on time to debug right now so want to do
something easy)
For my purpose, it is ok to make few errors is there a way I can put a
timeout on a function and the r-process neede
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