Dear Friends,
I have been scarce here. This is because I am busy implementing what I have
learned from you. You seem to have answered all my queries and I have not
got any new ones. I will quickly contact you as soon as I encounter
challenges in my analysis.
I hope you are well.
I have two recent
On 3/22/21 8:24 AM, francesca brun via R-help wrote:
Hello,
The problem was that version 4.0.4 did not support the package so I tried with
several old versions until 3.6.2 installs both climtrend and Rcmdr with its
graphical interface !! solved and thanks again Davide !!Francesca
I'm glad
Hello,
The problem was that version 4.0.4 did not support the package so I tried with
several old versions until 3.6.2 installs both climtrend and Rcmdr with its
graphical interface !! solved and thanks again Davide !!Francesca
(from Italy)
[[alternative HTML version deleted]]
Dear Berend, Mark, Jose, Arun, Great! Thank you so much for all your replies
with different codings. They all work well except one - because NAs in matrix A
need to take care of. Best,Zhengyu
> Subject: Re: [R] Ask for help: find corresponding elements between matrix
> From: b...@xs4all.nl
>
HI,
How do you want to combine the results?
It looks like the 5 datasets are list elements.
If I take the first three list elements,
imput1_2_3<-list(imp1=structure(list(ID = c("HM001", "HM001", "HM001", "HM001",
"HM001",
"HM001", "HM001", "HM001", "HM001", "HM001", "HM001", "HM001",
"HM001",
Hi,
I think I understand your mistake.
imput1_2_3<-list(imp1=structure(list(ID = c("HM001", "HM001", "HM001", "HM001",
"HM001",
"HM001", "HM001", "HM001", "HM001", "HM001", "HM001", "HM001",
"HM001", "HM001", "HM001"), CTIME = 1223:1237, WEIGHT = c(24.9,
25.2, 25.5, 25.24132, 25.7, 27.1, 27.3, 27
HI,
I don't have Amelia package installed.
If you want to get the mean value, you could use either ?aggregate(), or
?ddply() from library(plyr)
library(plyr)
imputNew<-do.call(rbind,imput1_2_3)
res1<-ddply(imputNew,.(ID,CTIME),function(x) mean(x$WEIGHT))
names(res1)[3]<-"WEIGHT"
head(res
Hi,
temp3<- read.table(text="
ID CTIME WEIGHT
HM001 1223 24.0
HM001 1224 25.2
HM001 1225 23.1
HM001 1226 NA
HM001 1227 32.1
HM001 1228 32.4
HM001 1229 1323.2
HM001 1230 27.4
HM001 1231 22.4236 #changed here to test the previous solution
",sep="",header=TRUE,stringsAsFactors=FALSE)
tempnew<- na.o
On 24/11/11 14:43, Bert Gunter wrote:
... and while I am at it, as this is the U.S. Thanksgiving...
My sincere thanks to the many R developers and documenters who
contribute large amounts of their personal time and effort to
developing, improving, and enhancing the accessibility of R for data
an
And from the side of a ordinary user who opened the page that read:
"Chapter 1: What is R?" two years ago to all of you on this list:
Since reading that first page things have changed so that I would get
through a normal working day without the software you create and the advice
you give.
Thank yo
Bert you said it better than I ever could. What R creators, developers, and
documenters do for us every day by how they effect our work as statisticians
is something I would not know how to measure. THANK YOU!
Frank
Bert Gunter wrote
>
> ... and while I am at it, as this is the U.S. Thanksgivin
Well said. +1
Dennis
On Thu, Nov 24, 2011 at 6:43 AM, Bert Gunter wrote:
> ... and while I am at it, as this is the U.S. Thanksgiving...
>
> My sincere thanks to the many R developers and documenters who
> contribute large amounts of their personal time and effort to
> developing, improving, and
... and while I am at it, as this is the U.S. Thanksgiving...
My sincere thanks to the many R developers and documenters who
contribute large amounts of their personal time and effort to
developing, improving, and enhancing the accessibility of R for data
analysis and science. I believe it is fair
Dear Uwe
Thank you very much for your reply.
Best,
Alex
Original-Nachricht
> Datum: Tue, 22 Nov 2011 15:41:17 +0100
> Von: Uwe Ligges
> An: french-connect...@gmx.net
> CC: r-help@r-project.org
> Betreff: Re: [R] logarithmically scaled y-axis in vioplot
>
>
> On 22.11.201
Dear r-community,
Today I have completed my PhD. I would like to take this opportunity to thank
the r-community for helping me with the r-coding. I use r to do data
manipulation during my PhD and I benefit a lot through the discussion in the
r-forum.
I will continue using R and help the ot
Hi Dennis
I was able to my problem. Thank you encouragement and time.
n<-7
newvars <- c(paste('m', rep(1:n, each = 4), rep(c('a', 'b')), rep(c('p1',
'p2'), each = 2), sep = ''))
newvars
[1] "m1ap1" "m1bp1" "m1ap2" "m1bp2" "m2ap1" "m2bp1" "m2ap2" "m2bp2" "m3ap1"
[10] "m3bp1" "m3a
Hi thereI appreciate for your reply.I am running into another problem now, the
following is my date (example)2000-1-4 -0.0383447182000-1-5
0.001952000-1-6 0.0009557022000-1-7 0.0270903842000-1-10
0.0111899662000-1-11-0.0130625692000-1-12 -0.004386331
I don't seem to get a problem with this. Have you tried a Monte Carlo
approach to verify that you are getting incorrect answers?
For me, I get when the upper is 1 that
> integrate(e2, lower = 0, upper = 1)
-0.2820948 with absolute error < 5e-05
> sum(e2(runif(1)))/1
[1] -0.2825667
whic
e2 <- function(x) {
out <- 0*x
for(i in 1:length(x))
out[i] <-integrate(function(y) qnorm(y),lower=0,upper=x[i])$value
out }
integrate(e2,lower=0, upper=a)$value
above is my code , when a is small , say a<0.45 the result is right .
however , when a>0.5
the result is incorrect .
Thank you very very much David
De : David Winsemius
à : David Winsemius
Envoyé le : Mardi, 25 Août 2009, 23h32mn 53s
Objet : Re: [R] Re : Odp: Re : Odp: Re : table function
On Aug 25, 2009, at 9:23 AM, David Winsemius wrote:
>
> On Aug 25, 2009, at 6:
Hi All,
I wish to thank all you guys out there. This is because of the help from you
guys I am able to learn how to use R in a short time.
Thanking you again for the help and quick responses.
Regards,
Rajat
--
Rajat,
PhD student
Industrial Engineering,
Texas Tech University,
Lubbock, TX, USA.
I also managed to get the right result but within a for loop ;)
So I really appreciate your solutions!
Thanks a lot!
--
View this message in context:
http://www.nabble.com/Using-grep-tp19881017p19882769.html
Sent from the R help mailing list archive at Nabble.com.
_
Yes! Again, thank you ALL very, very much.
Even simply lurking on the list generates many gems worth collecting.
DaveT.
>From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
>I totally agree both of you. This is a super place to mature the R.
>I learn a lot from this R heaven!
>Chunhao
>
>Quoting Es
I totally agree both of you. This is a super place to mature the R.
I learn a lot from this R heaven!
Chunhao
Quoting Esmail Bonakdarian <[EMAIL PROTECTED]>:
Tubin wrote:
In the past few weeks I have had to give myself a crash course in
R, in order
to accomplish some necessary tasks for my
Tubin wrote:
In the past few weeks I have had to give myself a crash course in R, in order
to accomplish some necessary tasks for my job. During that time, I've found
this forum to be helpful time and time again - usually I find the answer to
my problem by searching the archives; once or twice I
In the past few weeks I have had to give myself a crash course in R, in order
to accomplish some necessary tasks for my job. During that time, I've found
this forum to be helpful time and time again - usually I find the answer to
my problem by searching the archives; once or twice I've posted que
hi all!
Thank you for replying on my message. I will try all your suggestions.
Thank you again!
Filame
filame uyaco <[EMAIL PROTECTED]> wrote:
hi!
i send again my question because there was a problem earlier that
someone did not see my attached file. If you really can't download it,
Hi Jim,
What you told me works well.
I have tried using 'eval(parse(text="1:20 = x"))' as well as
'try(parse(text="1:20 = x"))' before but not using eval anfd try
functions together. I just added try function following your
suggestion, e.g. 'try(eval(parse(text="1:20 = x")))'and then it
w
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