Re: [R] Summing list with NA elements

one solution is to set NAs to 0, e.g., m <- matrix(1:3, 3, 3) x <- list(m, m+3, m+6) x[[1]][1] <- NA x. <- lapply(x, function (x) {x[is.na(x)] <- 0; x} ) Reduce("+", x.) I hope it helps. Best, Dimitris On 5/4/2012 11:19 AM, Evgenia wrote: I have a list ( in my real problem a double list y

Re: [R] Summing list with NA elements

I agree with you. I used this "trick" to take the desired results but I posted wondering If there was any other solution. Thanks Evgenia -- View this message in context: http://r.789695.n4.nabble.com/Summing-list-with-NA-elements-tp4608167p4608955.html Sent from the R help mailing list arc

Re: [R] Summing list with NA elements

Inelegant, but this is one way: Reduce(function(e1, e2){e1[is.na(e1)] <- 0; e2[is.na(e2)] <- 0; (e1 + e2)}, x) I.e., set the NAs to 0 before adding in the reduce function. Michael On Fri, May 4, 2012 at 5:19 AM, Evgenia wrote: > I have a list ( in my real problem  a double list y[[1:24]][[1:15

[R] Summing list with NA elements

I have a list ( in my real problem a double list y[[1:24]][[1:15]] but I think the solution would be the same) m <- matrix(1:3, 3, 3) x <- list(m, m+3, m+6) and as I want to have the sum of elements I use Reduce(`+`, x) having as result > Reduce(`+`, x) [,1] [,2] [,3] [1,] 12 12 12 [