Thompson, David (MNR ontario.ca> writes:
> Thank you Jim Holtman and Mark Leeds for your help.
>
> Original question:
> >How do I do the following more concisely?
> > Bout[is.na(Bout$bd.n), 'bd.n'] <- 0
> > Bout[is.na(Bout$ht.n), 'ht.n'] <- 0
> > Bout[is.na(Bout$dbh.n), 'dbh.n'] <- 0
Thank you Jim Holtman and Mark Leeds for your help.
Original question:
>How do I do the following more concisely?
> Bout[is.na(Bout$bd.n), 'bd.n'] <- 0
> Bout[is.na(Bout$ht.n), 'ht.n'] <- 0
> Bout[is.na(Bout$dbh.n), 'dbh.n'] <- 0
>. . .
Solution:
for (i in c('bd.n', 'ht.n', 'db
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