subject:"\[R\] Subset POSIXlt Field"

Re: [R] Subset POSIXlt Field

2010-10-05 Thread Ryan Garner

This should work: > test <-subset(wild,ID=="2830" & Date==as.POSIXlt("2010-08-17")) If not, here's another solution: > dates <- c("2010-05-28","2010-08-17") > dates <- as.POSIXlt(dates) > id <- c("2830","2830") > data <- data.frame(id,dates) > test <- data[data$id == "2830" & data$dates == as.POS

Re: [R] Subset POSIXlt Field

2010-10-05 Thread Phil Spector

Jared - The value "2010-08-17" is a character value, and your dates are stored as POSIXlt values. So you'd need to use Date == as.POSIXlt("2010-08-17") in your subset statement. - Phil Spector Statistic

[R] Subset POSIXlt Field

2010-10-05 Thread Jared Stabach

Hello All I, for the life of me, can't figure out to subset my dataframe by my Date field. The field has been formatted as POSIXlt. str(wild) .. $ Date: POSIXlt, format: "2010-05-28" "2010-05-28" "2010-05-28" ... This doesn't work: test <-subset(wild,ID=="2830" & Date=="2010-08-17"