Bill,
Thank you!! With some tweaking, this approach was exactly what I needed.
Previously, I had been using bxp and had my code for it, but my data was
structured completely differently from what I have now. I figured something
like groupedX <- with(d, split(x, group)) existed, but how to find it?
Does using zz<-bxp(boxplot(data,plot=FALSE)) do what you want? E.g.,
d <- transform(data.frame(t=1:15), x = sin(t)+log2(t), group =
paste("Group", t%/%4))
groupedX <- with(d, split(x, group))
zz <- bxp(boxplot(groupedX, plot=FALSE)) # bxp returns the x positions of
the boxes
points(col="blue", pc
something like this
points(zz[1:length(obs$value)], obs$value,lty=3,lwd=1,col="red",pch=19)
Sent from my iPhone
> On Jun 2, 2016, at 11:36, Thomas Adams wrote:
>
> points(zz, obs$value,lty=3,lwd=1,col="red",pch=19)
__
R-help@r-project.org mailing li
boxplot() turns the x variable into a factor, if it isn't already, so
the x axis is calibrated as seq_len(nvalues). Whatever you're trying
to do with using your boxplot object as the x variable in points won't
work: zz is a list of length 6.
There's an example in ?boxplot of adding points to a box
Hello all:
I've been beating my head on this for over a day and I have done a lot of
Google'ing with no luck.
I have generated a 'time-series' of boxplots (227), covering more than a
30-day period at 6-hour intervals, which summarize an ensemble forecast.
What I want to do is over-plot the observ
5 matches
Mail list logo