Hi Chris,
why not using routines for dates
dates <- c("09/10/2003", "10/22/2005")
format(strptime(dates,format="%m/%d/%Y"),"%Y")
or take just the last 4 chars from dates
gsub(".*([0-9]{4})$","\\1",dates)
cheers
Am 29.09.2011 16:23, schrieb Chris Conner:
> Help-Rs,
>
> I'm doing some string man
Chris Conner wrote on 09/29/2011 09:23:02 AM:
>
> Help-Rs,
>
> I'm doing some string manipulation in a file where I converted a
> string date in mm/dd/ format and returned the date .
>
> I've used regexpr (hat tip to Gabor G for a very nice earlier post
> on this function) in steps (
Help-Rs,
I'm doing some string manipulation in a file where I converted a string date in
mm/dd/ format and returned the date .
I've used regexpr (hat tip to Gabor G for a very nice earlier post on this
function) in steps (I've un-nested the code and provided it and an example of
what
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