The '[[' is just the index access to an object. type:
?'[['
to see the help page.
Actually I should have used '[' in this case:
> sapply(y, '[', 1)
[1] "1234567" "1234567" "1234567"
is equivalent to:
> sapply(y, function(a) a[1])
[1] "1234567" "1234567" "1234567"
>
So set a value based o
Yes, that was perfect! Thank you so much!
Just to clarify, since I'm kind of new to string manipulation-- is that '[['
in the sapply function what is designating splits/elements within the
string? So that's the part that says "I want this particular element" and
the "1" or "2" or "number" is what
On Fri, Feb 5, 2010 at 9:29 AM, jim holtman wrote:
> Does this help:
>
>> x <-
>> c("1234567.z3.abcdef-gh.12","1234567.z3.abcdef-gh.12","1234567.z3.abcdef-gh.12")
>> y <- strsplit(x, '[.]')
Here's another way with the stringr package:
library(stringr)
x <-
c("1234567.z3.abcdef-gh.12","1234567.
Does this help:
> x <-
> c("1234567.z3.abcdef-gh.12","1234567.z3.abcdef-gh.12","1234567.z3.abcdef-gh.12")
> y <- strsplit(x, '[.]')
>
> y
[[1]]
[1] "1234567" "z3""abcdef-gh" "12"
[[2]]
[1] "1234567" "z3""abcdef-gh" "12"
[[3]]
[1] "1234567" "z3""abcdef-gh" "12"
> y
I am currently attempting to split a long list of strings (let's call it
"string.list") that is of the format:
"1234567.z3.abcdef-gh.12"
I have gotten it to:
"1234567" "z3" "abcdef-gh" "12"
by use of the strsplit function.
This leaves me with each element of "string.list" having a split stri
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