And I'd like to add, just for the purpose of learning about R ... even if
wishes to use the loop version, there appears to be a misunderstanding of
R syntax.
The expression
1:225*100
does not produce 22500 numbers to put into the matrix, as apparently
expected.
Compare:
> 1:3*5
[1] 5 10
On Tue, Jun 12, 2012 at 12:24 AM, Rody wrote:
> I found a solution myself, but thanks for the answers. I solved it like this:
> D <- matrix(1:225*100,nrow=100,ncol=225)
> for(i in 1:225)
> D[,i] <- rt(100,df=225)
> end
but as Don said, you can do this in one step (and it is both faster
and mo
I found a solution myself, but thanks for the answers. I solved it like this:
D <- matrix(1:225*100,nrow=100,ncol=225)
for(i in 1:225)
D[,i] <- rt(100,df=225)
end
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This does tend to look like homework, but...
If you want them in one vector, then that vector will have length 225*100,
of course. So rt(225*100,225) would do it. Or you could use the matrix()
function to convert this to a matrix. See ?matrix.
-Don
--
Don MacQueen
Lawrence Livermore National L
Take a look at ?replicate.
Michael
On Jun 9, 2012, at 5:16 AM, Rody wrote:
> Hi everyone
>
> I need to make a work for school in R and one of my questions is to create
> 225 datasets of 100 observations and they need to be t_225 distributed. So,
> I know how to make one dataset (rt(100,df=225
Hi everyone
I need to make a work for school in R and one of my questions is to create
225 datasets of 100 observations and they need to be t_225 distributed. So,
I know how to make one dataset (rt(100,df=225)), but how can I store those
225 in one vector, array,.. ?
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