Thankyou very much. It worked.
Eliza
From: Bert Gunter
Sent: Friday 15 April 2022 17:00
To: Jeff Newmiller
Cc: R-help ; Eliza Botto
Subject: Re: [R] Sorted index of values in matrix
...
But Ivan's solution -- which I had to think about -- is better, a
... and here is another version of Jeff's solution using the built in
row() and col() functions instead of explicitly creating the indices
(but his version generalizes to arbitrary arrays; this does not):
qq <- matrix(12:7, nrow =3) ## start with a non-sorted matrix
> qq
[,1] [,2]
[1,] 12
В Fri, 15 Apr 2022 14:53:36 +
Eliza Botto пишет:
> sort(qq) command will execute the sorted values of this matrix as (1
> 2 3 4 5 6). Instead of values, I want the row and column names of
> these sorted values as (1,1), (1,2), (1,3), (2,1), (2,2), (2,3)
Combine order() to get the sorting per
deaR useRs,
I have this following simple dataset
> dput(qq)
structure(1:6, .Dim = 3:2, .Dimnames = list(c("1", "2", "3"),
c("1", "2")))
I want to extract row and column index of the sorted values of this matrix
For example,
sort(qq) command will execute the sorted values of this matrix as
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