On 24-03-2012, at 05:35, Shant Ch wrote:
> Hello all,
>
> I was going to solve (n-m)! * (n-k)! = 0.5 *n! * (n-m-k)!
>
> for m when values of n and k are provided
>
>
> n1<-c(10,13,18,30,60,100,500) # values of n
>
> kx<-seq(1,7,1); # values of k
>
>
>
Hello all,
I was going to solve (n-m)! * (n-k)! = 0.5 *n! * (n-m-k)!
for m when values of n and k are provided
n1<-c(10,13,18,30,60,100,500) # values of n
kx<-seq(1,7,1); # values of k
slv2<-lapply(n1,function(n){
slv1<-lapply(kx,function(k){
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