Here are two options that might work for you given the little bit you've said:
## If its the same parameter all 30 times
## say, for example, base = 4.5 to log
for(i in 1:30) {
print(log(1:10, base = 4.5))
}
## if they are different parameters, you could try
lapply(X = c(1.3, 3, 2.2, 4, 5), FUN
Isn't it what do.call() does?
Ivan
Le 12/1/2010 16:39, Lamke a écrit :
Thank you so much Joshua. That's exactly what I am looking for.
What I wanted to do is to pass a parameter to a function and I have to run
the functions 30 times. Instead of typing them all out, I created a long
string of
Thank you so much Joshua. That's exactly what I am looking for.
What I wanted to do is to pass a parameter to a function and I have to run
the functions 30 times. Instead of typing them all out, I created a long
string of "f(a);f(b);f(c) ..." using paste() and use eval and parse to
evaluative t
Hi Kel,
Try this:
eval(parse(text = a))
x
Many times (though certainly not all), it may be easier/cleaner to
rethink what you are doing (the step before you get a <- "x <- 2^2")
to see if there is a simpler way.
Cheers,
Josh
On Tue, Nov 30, 2010 at 2:24 PM, Lamke wrote:
>
> Hi group,
>
> I d
Hi group,
I did some searches about this very simple question. Hope someone can help
me out.
If I have the following:
a <- "x <- 2^2"
a
[1] "x <- 2^2"
How do I evaluate the expression that gets me an answer of 4? I tried the
following:
> eval(a)
[1] "x <- 2^2"
> get(a)
Error in get(a) : obj
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