Yes the lapply function sorted it out. Thanks for the advice.
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On Feb 14, 2012, at 8:44 AM, geotheory wrote:
Basic question (if you know the answer)... I am dealing with a list
of
commonly-formatted sub-lists, for example:
l <- list("")
l[[1]] <- c("A1","A2","A3")
l[[2]] <- c("B1","B2","B3")
l[[3]] <- c("C1","B2","B3")
Lets say I need to extract every
How about:
l <- list("")
l[[1]] <- c("A1","A2","A3")
l[[2]] <- c("B1","B2","B3")
l[[3]] <- c("C1","B2","B3")
lapply(l, "[[", 2)
or
sapply(l, "[[", 2)
I hope it helps.
Best,
Dimitris
On 2/14/2012 2:44 PM, geotheory wrote:
Basic question (if you know the answer)... I am dealing with a li
Basic question (if you know the answer)... I am dealing with a list of
commonly-formatted sub-lists, for example:
l <- list("")
l[[1]] <- c("A1","A2","A3")
l[[2]] <- c("B1","B2","B3")
l[[3]] <- c("C1","B2","B3")
Lets say I need to extract every 2nd item (i.e. A2, B2, C2). [[]] cannot be
used.
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