On Aug 25, 2011, at 1:30 PM, Claudio Zanettini wrote:
I tried setting ylim=(0, 1000)
but the segment that I have draw is at y=-10
so if I set the y origin to 0 I don t have the segment,
if a l leave it at -10 I have the segment but the axis start from
-10.
I would like to have both.
So to h
I'm not really sure what you are asking for, but I might venture to suggest
a few ideas:
1) Do you mean to say you want two plots: one with ylim around -10 and the
other running from 0 to 1000?
2) Are you looking for a "break" in the y-axis? If so, plotrix may be able
to help, but it's hardly wor
> I tried setting ylim=(0, 1000)
> but the segment that I have draw is at y=-10
> so if I set the y origin to 0 I don t have the segment,
> if a l leave it at -10 I have the segment but the axis start from -10.
>
> I would like to have both.
> So to have a graph with ylim=( 0, 1000)
> and under it
"lim" is not the argument: "ylim" is.
You put in a vector of length 2 comprising the min and max y you wish:
consider this:
x = -5:5; y = x^2; z = rep(-5,11);
layout(1:2)
plot(x,y,type="b"); lines(x,z,col=2)
plot(x,y,ylim = c(-8,max(y)+3),type="b"); lines(x,z,col=2)
For your work, you'd need yli
Yes I tried but if I set the lim to 0 then it will not displayed the line
that is at -10, right?
2011/8/25 R. Michael Weylandt
> Look at ylim, as an optional argument to plot.
>
> Michael
>
> On Thu, Aug 25, 2011 at 1:07 PM, Claudio Zanettini <
> claudio.zanett...@gmail.com> wrote:
>
>> Hello ev
Look at ylim, as an optional argument to plot.
Michael
On Thu, Aug 25, 2011 at 1:07 PM, Claudio Zanettini <
claudio.zanett...@gmail.com> wrote:
> Hello everyone,
> I have a graph and a segment parallel to the x axis at y=-10, x=0, and
> bars on it.
> Now the question is,
> Is there a way to le
Hello everyone,
I have a graph and a segment parallel to the x axis at y=-10, x=0, and
bars on it.
Now the question is,
Is there a way to leave the segment there but let the graph axis start from
the origin?
In this way the segment will be out of the graph
Thanks
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