On Mar 6, 2012, at 6:19 PM, FU-WEN LIANG wrote:
Thanks for your advise, David.
I did read the help for survreg and using the followings to calculate.
survreg's scale =1/(rweibull shape)
survreg's intercept = log(rweibull scale)
However, the scale in rweibull has been transformed by exp(
Thanks for your advise, David.
I did read the help for survreg and using the followings to calculate.
survreg's scale =1/(rweibull shape)
survreg's intercept = log(rweibull scale)
However, the scale in rweibull has been transformed by exp(betaX's). In my
case, the baseline hazard for T is 0
On Mar 6, 2012, at 5:53 PM, FU-WEN LIANG wrote:
Hi all,
I'm trying to generate a Weibull distribution including four
covariates in
the model. Here is the code I used:
T = rweibull(200, shape=1.3,
scale=0.004*exp(-(-2.5*b1+2.5*b2+0.9*x1-1.3*x2)/1.3))
C = rweibull(n, shape=1.5, scale=0.008)
Hi all,
I'm trying to generate a Weibull distribution including four covariates in
the model. Here is the code I used:
T = rweibull(200, shape=1.3,
scale=0.004*exp(-(-2.5*b1+2.5*b2+0.9*x1-1.3*x2)/1.3))
C = rweibull(n, shape=1.5, scale=0.008) #censoring time
time = pmin(T,C) #observed time is m
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