yes, the data.frame is exactly the same as the one I posted earlier.
I was trying to see if the loop function works. And I got that message. here
below is the syntax I was trying to run, followed by the error message at
the end:
> sampleX<-function(X,nGrp1,nsamples){if(nGrp1>=4)stop("can't sampl
On 16 November 2010 16:10, wangwallace wrote:
>
> Michael, I really appreciate your help.
>
> but I got the following error message when I wan trying to run the function
> written by you:
>
> Error in out[i, ] <- apply(help[, c(grp1 + 1, grp2 + 5)], 2, sample, 1) :
> number of items to replace is
Michael, I really appreciate your help.
but I got the following error message when I wan trying to run the function
written by you:
Error in out[i, ] <- apply(help[, c(grp1 + 1, grp2 + 5)], 2, sample, 1) :
number of items to replace is not a multiple of replacement length
I am not quite sure
Hello,
Is this what you want ?
sampleX <- function(X, nGrp1, nsamples)
# X is matrix or data.frame with cols for two groups of variables
# with grp1 in cols 2:5 and grp2 in cols 6:9
#
# nGrp1 <- number of variables to sample from group 1
#
# nsamples <- number of rows in output matrix
if (nGrp
Hey,
I am hoping someone can help me with a sampling question.
I have a data frame of 8 variables (the first column is the subjects' id):
SubIDCSE1 CSE2 CSE3 CSE4 WSE1 WSE2 WSE3 WSE4
1 6 5 6 2 6 22 4
2 6 4
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