Dear Rolf,
You are of course quite right, however I wish the diagonal to be
ignored by setting the value to zero. The inf was just recognising the
flow value from self to self.
A very fair point though.
Best,
Nick
On 15 November 2012 04:10, Rolf Turner wrote:
> On 15/11/12 11:13, Nick Duncan wrot
On 15/11/12 11:13, Nick Duncan wrote:
Dear All,
I have a matrix in which the diagonal has the string "Inf" in it. In
order to be able to do cluster analysis this needs to be replaced with
a Zero.
I am very sceptical about this assertion. "Inf" means infinity
which is of course *NOT* t
Cc: r-help@r-project.org
Sent: Wednesday, November 14, 2012 7:14 PM
Subject: Re: [R] Replacing string in matrix with zero
Hello,
I doubt your Inf is a string, R does have the numeric value Inf (and
-Inf), just try 1/0.
As for the question,
x <- matrix(1:9, ncol = 3)
diag(x) <- 1/0
x
x[x ==
Hello,
I doubt your Inf is a string, R does have the numeric value Inf (and
-Inf), just try 1/0.
As for the question,
x <- matrix(1:9, ncol = 3)
diag(x) <- 1/0
x
x[x == Inf] <- 0
x
Note that it could also be diag(x) <- 0
Hope this helps,
Rui Barradas
Em 14-11-2012 22:13, Nick Duncan escreve
You can use ifelse()
#Create data for example
x <- matrix(data=c(Inf, 2, 3, 4, Inf, 6, 7, 8, Inf), nrow=3)
#Turn Inf into zero.
x <- ifelse(x == Inf, 0, x)
Jeremy
On 14 November 2012 14:13, Nick Duncan wrote:
> Dear All,
>
> I have a matrix in which the diagonal has the string "Inf" in it.
Dear All,
I have a matrix in which the diagonal has the string "Inf" in it. In
order to be able to do cluster analysis this needs to be replaced with
a Zero.
I can do this by putting it into Excel, replacing and putting it back
into R but it's tedious, and I am sure there is a simple way to do it
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