thanks a lot deepayan,
I will study carefully your code!
thanks
max
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On Fri, Jun 22, 2012 at 5:50 PM, maxbre wrote:
> Given my reproducible example
>
> myexample<-structure(list(site = structure(c(4L, 2L, 2L, 4L, 2L, 4L, 4L,
> 3L, 1L, 3L, 1L, 1L, 3L, 4L, 5L, 2L), .Label = c("A", "B", "C",
> "D", "E"), class = "factor"), obs = c(0.302, 0.956, 0.72, 1.21,
> 0.887, 0.
Sorry, missed the plot instruction.
dotplot(sample[ord] ~ obs[ord] | site, data=myex,
[... etc ...]
Rui Barradas
Em 22-06-2012 16:43, Rui Barradas escreveu:
Hello,
Ok, I hadn't understood. I still don't, not completely. Why do you
want to order 'sample' with reference to 'ob
Hello,
Ok, I hadn't understood. I still don't, not completely. Why do you want
to order 'sample' with reference to 'obs'? It would make sense only in
the case of 'obs' ties. Doesn't it make more sense to order 'sample'
within 'site'?
As for keeping 'sample' character it's very simple, I was
thanks for your reply but I don't think your solution can accomplish to what
I need...
(I can't see any ordering of the variable "sample" with reference to the
variable "obs")
please keep in mind that for a numer of reasons that I do not mention here
for the sake of conciseness in my case the vari
Hello,
Try the following
myex <- myexample
myex$sample <- as.character(myex$sample)
myex$sample <- as.Date(myex$sample, format="%d/%m/%Y")
myex
Then, run the first attempt without bothering to order, lattice is
clever and will do it for you.
Hope this helps,
Rui Barradas
Em 22-06-2012 13:2
Given my reproducible example
myexample<-structure(list(site = structure(c(4L, 2L, 2L, 4L, 2L, 4L, 4L,
3L, 1L, 3L, 1L, 1L, 3L, 4L, 5L, 2L), .Label = c("A", "B", "C",
"D", "E"), class = "factor"), obs = c(0.302, 0.956, 0.72, 1.21,
0.887, 0.728, 1.294, 20.493, 0.902, 0.031, 0.468, 2.318, 4.795,
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