Thomas,
There are many approaches tried over the years to do partitioning along the
lines you mentioned and others. R already has many built-in or in packages
including some that are quite optimized. So anyone doing serious work can
often avoid doing this the hard way and build on earlier work.
N
I was wondering if this is a good alternative method to split a data column
into distinct groups.
Let's say I want my first group to have 4 elements selected randomly
mydata <- LETTERS[1:11]
random_grp <- sample(mydata,4,replace=FALSE)
Now random_grp is:
> random_grp
[1] "H" "E" "A" "D"
# How's
I apologise for not following up in-thread, as I used to use Gmane to
reply to postings read digested before its (hopefully temporary) demise.
The problem is that the CRAN OSX binaries for rgdal are shipping without
two key folders, proj/ and gdal/. Until we get it fixed, please see if you
can
I would hope that if you have an R script that is running for a month that
you have built in periodic checkpoints so that you can recover what is
happening. In cases where I want to be able to restart an R script at some
point downstream, I will "save.image", or just the objects that are
important
Not a question about R (it is about process management in what I am guessing is
some kind of unix-alike OS).
I suspect that unless you wrote log files or intermediate data to disk as you
went, it is very likely that you are out of luck. Since you are posting here
instead of reviewing those file
Dear group
I had a tmux session, on it an R script is running before the program should
ends
on the screen written "killed" and the script terminated and returned bake to
bash (in the same tmux window)
Q: how can I re attach into the killed R session and check it? can I recover
what was the s
Hi Frederik
Goodo, glad you found mvbutils::mvb.parent.frame useful. I had forgotten that
it's in mvbutils rather than debug package. This all dates back about 15
years...
To be fair, I don't think R's behaviour with duplicated-but-aliased frames in
the call stack is a "bug"--- everything norm
Thanks, Mark - I'm taking up your invitation to forward your message
to the list just because it gives us some valuable data on (1) how
long the behavior has been around, and (2) how many other people
(don't) understand the behavior, and (3) how we might fix or work
around it.
I notice some other
You MIGHT get an answer here, but this type of question is more likely to
belong on the R-devel mailing list than here. See the Posting Guide.
--
Sent from my phone. Please excuse my brevity.
On December 1, 2016 8:20:52 AM PST, lejeczek via R-help
wrote:
>hi everyone.
>
>this will be a bit r
hi everyone.
this will be a bit rpm packaging related, not sure if more
than R itself but before going to rpm gang I hoped someone
here knows:
why this:
byte-compiling package 'compiler'
Warning in file(datafile, "wb") :
cannot open file
'/usr/lib64/R-MY/lib64/R/library/compiler/R/compiler
and
maybe others in future) in
understanding and solving the problem.
Thank you
Best regards
Angelo
>Messaggio originale
>Da: bgunter.4...@gmail.com
>Data: 26-nov-2015 3.24
>A: "angelo.arc...@virgilio.it"
>Cc: , "r-help@r-project.org"
>Ogg: Re: [R]
At this point, it seem obvious to me that you would benefit by local
statistical consulting, rather than further badgering on this list, as
you seem confused by both the underlying statistical concepts and how
they need to be handled in R/car. Pursuing your current course seems
destined to lead to
Dear Prof. John Fox,
thanks a lot for your answer. Do you mean that my data set should have 19 rows
(one for each of the 19 subjects)
and 144 columns (that is 72 trials * 2 dependent variables)? So should the
dataframe look like this?
Subject Stimulus_1.Centroid.repetition1 Stimulus_1.Ce
Dear Prof. Andrew Robinson,
I am very grateful to you for your enlightening answer
All the best
Angelo
Messaggio originale
Da: a.robin...@ms.unimelb.edu.au
Data: 23-nov-2015 20.50
A: "angelo.arc...@virgilio.it"
Cc: "R help (r-help@r-project.org)"
Ogg: Re: [R] Question about lme
Dear prof. Fox,
thank you very much
Best regards
Angelo
>Messaggio originale
>Da: j...@mcmaster.ca
>Data: 23-nov-2015 12.50
>A: "angelo.arc...@virgilio.it"
>Cc: "r-help@r-project.org"
>Ogg: RE: [R] How to plot results from lme in presence of a significant
interaction
>
>Dear Angelo,
>
Dear Bert and R list,
actually I had tried the interaction plot function, but I deduced that it was
not the correct function since it gave me an empty plot (no lines). This should
not be correct because as you can see from the results of the analysis I
reported in the previous e-mail, there is
1-lug-2015 11.58
A:
"angelo.arc...@virgilio.it<mailto:angelo.arc...@virgilio.it>"mailto:angelo.arc...@virgilio.it>>,
mailto:bgunter.4...@gmail.com>>
Cc: mailto:r-help@r-project.org>>
Ogg: Re: R: Re: [R] R: Re: Differences in output of lme() when introducing
interactions
Dear Terry,
I am very grateful to you for such a detailed and helpful answer.
Following your recommendation then I will skip the method presented at
http://www.ats.ucla.edu/stat/r/faq/type3.htm
So far, based on my understanding of R I arrived to the conclusion that the
correct way to see if ther
work.
John Kane
Kingston ON Canada
> -Original Message-
> From: angelo.arc...@virgilio.it
> Sent: Tue, 21 Jul 2015 12:12:58 +0200 (CEST)
> To: li...@dewey.myzen.co.uk, bgunter.4...@gmail.com
> Subject: [R] R: Re: R: Re: R: Re: Differences in output of lme() when
> introd
with R?
My department does not have a statician, so I have to find a solution with my
own capacities.
Thanks in advance
Angelo
Messaggio originale
Da: li...@dewey.myzen.co.uk
Data: 21-lug-2015 11.58
A: "angelo.arc...@virgilio.it",
Cc:
Ogg: Re: R: Re: [R] R: Re: Diff
help? Any online reference to-the-point
that can help me in solving this problem?
Thank you in advance
Best regards
Angelo
Messaggio originale
Da: bgunter.4...@gmail.com
Data: 21-lug-2015 3.45
A: "angelo.arc...@virgilio.it"
Cc: ,
Ogg: Re: [R] R:
l.com
Data: 21-lug-2015 3.45
A: "angelo.arc...@virgilio.it"
Cc: ,
Ogg: Re: [R] R: Re: Differences in output of lme() when introducing interactions
I believe Michael's point is that you need to STOP asking such
questions and START either learning some statistics or work with
someone who alr
I believe Michael's point is that you need to STOP asking such
questions and START either learning some statistics or work with
someone who already knows some. You should not be doing such analyses
on your own given your present state of statistical ignorance.
Cheers,
Bert
Bert Gunter
"Data is
Dear Michael,
thanks for your answer. Despite it answers to my initial question, it does not
help me in finding the solution to my problem unfortunately.
Could you please tell me which analysis of the two models should I trust then?
My goal is to know whether participants’ choices
of the depend
p@r-project.org", "John Fox"
Ogg: RE: [R] R: RE: Bonferroni post hoc test in R for repeated measure ANOVA
with mixed within and between subjects design
Angelo,
the conservatism of Bonferroni aside for a moment, I don't really see what you
are after.
mcp(Emotion = "Tukey&q
-Messaggio originale
Da: j...@mcmaster.ca
Data: 7-lug-2015 3.23
A: "angelo.arc...@virgilio.it"
Cc: , "r-help@r-project.org"
Ogg: Re: [R] R: RE: Bonferroni post hoc test in R for repeated measure ANOVA
with mixed within and between subjects design
Dear Angelo,
The Bonferroni
Thank you John, so far the easiest way is to use ezanova() since I do not have
to reorder the data
and create iframe etc.
Best
Messaggio originale
Da: pda...@gmail.com
Data: 7-lug-2015 10.12
A: "John Fox"
Cc: ,
Ogg: Re: [R] Sphericity for a repeated measure ANOVA with whithin and b
Fox [mailto:j...@mcmaster.ca]
> Sent: Dienstag, 7. Juli 2015 03:24
> To: angelo.arc...@virgilio.it
> Cc: Meyners, Michael; r-help@r-project.org
> Subject: Re: [R] R: RE: Bonferroni post hoc test in R for repeated measure
> ANOVA with mixed within and between subjects design
>
&g
Dear Angelo,
The Bonferroni p-value is just the ordinary p-value times the number of tests,
so, since R supports multiplication, you can apply the Bonferroni adjustment in
R. Because Bonferroni tests for multiple comparisons can be very conservative,
asking why you want to use them is a fair qu
Dear Michael,
thank you for your answer, however, I am not asking for the tukey
with the bonferroni adjustment, but doing the post hoc with the bonferroni
method.
Apparently this is done easily in SPSS, I am wondering whether it is possible
with R.
Can anyone help me?
Thanks in advance
Angelo
Hi,
Here I use the data.frame b as an example to show how it can be
accomplished. The sixth column of b has values 6 through 996 by an
increment of 10. The statement
sapply(b[,6],function(x)if(x==6){0}else{if(x==996){2}else{1}}) assigns 0 to
6, 2 to 996 and 1 to the rest in column 6. In your
Thursday, January 22, 2015 10:29 AM
To: Bert Gunter
Cc: William Dunlap; r-help@r-project.org; Ravi Varadhan
Subject: Re: [R] Re-order levels of a categorical (factor) variable
>>>>> Bert Gunter
>>>>> on Wed, 21 Jan 2015 18:52:12 -0800 writes:
> Bill/Rav
> Bert Gunter
> on Wed, 21 Jan 2015 18:52:12 -0800 writes:
> Bill/Ravi:
> I believe the problem is that the factor is automatically created when
> a data frame is created by read.table(). By default, the levels are
> lexicographically ordered. The following reproduces
Bill/Ravi:
I believe the problem is that the factor is automatically created when
a data frame is created by read.table(). By default, the levels are
lexicographically ordered. The following reproduces the problem and
gives a solution.
>library(lattice)
> z <- data.frame(y = 1:9, x = rep(c("pre"
Are you sure the factors of T are in the order you think they are? (Are you
sure you are using the expected version of T.) Use print(levels(T)) to
make
sure.
I tried
timeCats <- c("Presurgery", "Day 30", "Day 60", "Day 180", "Day 365")
d <- data.frame(T = factor(rep(timeCats, 11:15), lev
Hi,
I have a fairly elementary problem that I am unable to figure out. I have a
continuous variable, Y, repeatedly measured at multiple times, T. The variable
T is however is coded as a factor variable having these levels: c("Presurgery",
"Day 30", "Day 60", "Day 180", "Day 365").
When I plot
Hello !
Yes, I realized just after sending you the email that I didn't cc the list, so
I sent it again just after that.
And thank you very much for your help, it works perfectly !
And the package I used was ncf.
Sarah
Message d'origine
De : Rui Barradas
Date :
A : Sar
For future reference, perhaps creating an index variable when the data
frame is first created and before ³multiple process and ordering² is done
would be good.
mydat$index <- seq(nrow(mydat))
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925
Hello,
If your data.frame is named 'dat', try something like the following.
dat[order(rownames(dat)), ]
Hope this helps,
Rui Barradas
Em 28-08-2014 08:56, Ragia Ibrahim escreveu:
Dear all,
I have a data frame, where multible process and ordering done ..can I re
arrange (re order ) it rega
Dear all,
I have a data frame, where multible process and ordering done ..can I re
arrange (re order ) it regarding it' s original ROW index ? how?
example
Xi items numrber_list_items
38 8, 7, 3, 44
27 7, 3, 40
1 10 10
...
>
>----------
>Sent from my Nokia
>
>--Original message--
>From: pascalbe...@libero.it
>To:
>Date: Wednesday, April 30, 2014 9:40:06 AM GMT+0200
>Subject: R: Re: [R] dataframe
>
>thank you for your help but it doesn't work
>
>James
>
ot;Treatment"), class = "factor"), rt = c(NA, NA,
NA, 195.09555), mz = c(NA, NA, NA, 61.00722661), o066_010 = structure(c(9L,
7L, 8L, 2L), .Label = c("14043676.02", "14536204.77", "17652481.49",
"5212485.416", "6731535.564", "9876651.476&
on what you are
willing to assume.
From: Zhiyuan Sun [sam.d@gmail.com]
Sent: Friday, March 21, 2014 10:48 PM
To: Therneau, Terry M., Ph.D.
Cc: r-help@r-project.org
Subject: Re: [R] [Re: Does a survival probability(the probability not,
experiencing
Thanks Terry. Your explanation is right on the point. You solved my
question about time-dependent covariate. When calculating survival at
time t, you have to consider the exposure history before ant at time
t. It is reasonable when we assume cumulative hazard before time t
can be carried over to
On 03/20/2014 06:00 AM, r-help-requ...@r-project.org wrote:
My question is related to a cox model with time-dependent variable.
When I think about it more, I get a little confused about
non-increasing assumption for survival probability for an individual.
For example, for a time-dependent ,say
erent lengths
from an existing vector and create a matrix, visit
http://r.789695.n4.nabble.com/template/NamlServlet.jtp?macro=unsubscribe_by_code&node=4685783&code=ZWxpc2FiZXR0YS5wZXRyYWNjaUBnbWFpbC5jb218NDY4NTc4M3w4ODEyMDMyNDg=
--
View this message in context:
http://r.789695.n4.nabbl
Hello, I am using the R2Bayesx package to fit a GAM to time-series data and
then using this model to extrapolate beyond the extent of the time-series. The
prediction.bayesx function works quite well to predict the series, but does not
seem to provide uncertainty estimates for the prediction. The
.com
Cc:
Sent: Tuesday, October 8, 2013 11:48 AM
Subject: R: Re: R: Re: [R] Information Frequency problem calculation
Dear Master, I want to count separate it is another category
>Messaggio originale
>Da: smartpink...@yahoo.com
>Data: 08/10/2013 17.30
>A: "jarod..
I am running a large mixed model, 65k entries on 11 fixed effects and one
random. One of the fixed effects is "Course" a factor that takes on 14
different values
>levels(Master.complete$Course)
[1] "B101" "B2A" "B2B" "B2C" "C118A" "C118B" "C118C" "C2A" "C2B"
[10] "C2C" "N101" "P7A" "
Dear Uwe,
- Message d'origine -
De : Uwe Ligges
Envoyés : 22.09.13 10:55
À : John Gonzalez
Objet : Re: Re : Re: [R] Re : Privacy rights of an old user of this list
>> On 21.09.2013 22:40, John Gonzalez wrote:
>> As I said previously, I'm only concerned about wha
Hi A.K.,
This is exactly what I needed:
x <- data.frame(Month = airquality$Month, Day = as.character(airquality$Day))
y <- aggregate(x$Day ~ x$Month, data = x, paste, collapse = ", ")
write.table(y, "y.txt", row.names = FALSE, quote = FALSE, sep = '\t')
The trick is to use collapse in the aggreg
John
- Message d'origine -
De : Uwe Ligges
Envoyés : 21.09.13 10:26
À : Adan Leobardo Martinez Cruz
Objet : Re: [R] Re : Privacy rights of an old user of this list
The locations where the mailing list are archived are not even
controlled by any member of R-core or the R foundat
,
John
- Message d'origine -
De : Uwe Ligges
Envoyés : 21.09.13 10:26
à : Adan Leobardo Martinez Cruz
Objet : Re: [R] Re : Privacy rights of an old user of this list
The locations where the mailing list are archived are not even controlled by
any member of R-core or the R foundat
emius; Albin Blaschka; Duncan Murdoch; Jeff Newmiller; S
> Ellison; Jim Lemon
> Cc: r-help@r-project.org
> Subject: [R] Re : Privacy rights of an old user of this list
>
> I would like to thank David for letting me publish this and discuss it
> openly. I must acknowledge from the a
-help-boun...@r-project.org] on behalf of
John Gonzalez [john.gonza...@gmx.fr]
Sent: Monday, September 16, 2013 5:14 PM
To: David Winsemius; Albin Blaschka; Duncan Murdoch; Jeff Newmiller; S
Ellison; Jim Lemon
Cc: r-help@r-project.org
Subject: [R] Re : Privacy rights of an old user of this list
I
behalf of
John Gonzalez [john.gonza...@gmx.fr]
Sent: Monday, September 16, 2013 5:14 PM
To: David Winsemius; Albin Blaschka; Duncan Murdoch; Jeff Newmiller; S
Ellison; Jim Lemon
Cc: r-help@r-project.org
Subject: [R] Re : Privacy rights of an old user of this list
I would like to thank David for
I would like to thank David for letting me publish this and discuss it openly.
I must acknowledge from the answers that I received to my post, that the
administrators of this list are doing what seems to be fair to me: what most
people demand or understand that is right.
However I don't share yo
> vec = matrix(data=round(rnorm(15,1,2)),ncol=3)
> vec
[,1] [,2] [,3]
[1,]11 -1
[2,]62 -1
[3,]002
[4,]0 -3 -2
[5,]112
> rowMeans(vec)
[1] 0.333 2.333 0.667 -1.667 1.333
> apply(vec,1,mean)
[1] 0.333 2.333 0.
Thanks for the workaround and the explanation
Alain
De : Milan Bouchet-Valat [nalimi...@club.fr]
Date d'envoi : vendredi 28 juin 2013 19:20
À : LE TERTRE Alain
Cc : 'R-help@r-project.org'
Objet : Re: [R] use of formula in survey analysis with replicated wei
I have not experienced that, but have you tried to see if killing the
processes helps? On Windows CTRL+ALT+DEL usually brings up the system
monitor or whatever it's called, where you can see programs and processes
currently running. If your R gets stuck in a loop then you may see some
refer
Have not experienced that.
---
Jeff NewmillerThe . . Go Live...
DCN:Basics: ##.#. ##.#. Live Go...
Live: OO#.. Dead: OO#.. Playi
Hi all,
It is really annoying. The first time starting R, it works, but I cannot
re-start R unless re-start my PC. Operation system is Win7.
Anyone knows how to deal with issue?
Cheers,
Xiaoping
**
IMPORTANT: This e-mail is
Hi andrija djurovic,
Thanks a lot for your replyand for your useful suggestions.
Actually I need to run this script without user interaction, so when it is
required to input Village I need to pass it automatically not by the user.
Regards,
Vahe
[[alternative HTML version deleted]]
http://www.scenedenuit.com/xmwln/zwfpfz.nkeiq
Hey Sky
4/8/2013 4:12:17 PM
cbcdvutdvqnlpwsxx
tmuadh
[[alternative
nomogram does not have an option for specifying a new order for the
variables. With some exceptions you should be able to reorder the variables
in the model formula to achieve the desired result.
Frank
Eleni Rapsomaniki-3 wrote
> Hi,
> I am using the function "nomogram" in the rms package for sur
Hi,
I am using the function "nomogram" in the rms package for survival analysis.
How is the order in which variables determined and how can I change it? I use
it with a cph() model.
Many Thanks
Eleni Rapsomaniki
Clinical Epidemiology Group
Department of Epidemiology and Public Health
University
Hi
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of jeharmse
> Sent: Monday, March 11, 2013 5:28 PM
> To: r-help@r-project.org
> Subject: Re: [R] Re move row.names column in dataframe
>
> > 1.
Thank you. This does what I want (apparently by coercing data.frame to list
with no other structure).
--
View this message in context:
http://r.789695.n4.nabble.com/Remove-row-names-column-in-dataframe-tp856647p4661049.html
Sent from the R help mailing list archive at Nabble.com.
_
> 1.If your data frame is numeric, change it to matrix.
It isn't necessarily numeric.
> 2.Or make your own function
I think that's the solution, but the function has to handle both NA and
non-numeric.
equal.NA <- function(x,y)
all(is.na(x)==is.na(y)) && all(is.na(x) | x=
On 2013-03-11 06:07, Jorgen Harmse wrote:
identical(df[1,],df[2,]) is FALSE because of the row names. all( == ) is just a
work-around that I attempted.
Jorgen.
I would just wrap the elements in c():
identical( c(df[1,]), c(df[2,]) )
Peter Ehlers
On Mar 11, 2013, at 02:53 , PIKAL Petr w
as.character instead of as.numeric, the result will be probably
same (except the warning)
Regards
Petr
From: Jorgen Harmse [mailto:jorgen.har...@civitaslearning.com]
Sent: Monday, March 11, 2013 2:08 PM
To: PIKAL Petr
Cc: r-help@r-project.org
Subject: Re: [R] Re move row.names column in dataframe
id
identical(df[1,],df[2,]) is FALSE because of the row names. all( == ) is just a
work-around that I attempted.
Jorgen.
On Mar 11, 2013, at 02:53 , PIKAL Petr wrote:
>>
>>> df <- data.frame(x=c(1,1,NA,NA), y=c(2,2,7,7))
>>> identical(df[1,],df[2,])
>> [1] FALSE
>>> all(df[1,]==df[2,])
>> [1] TRU
Hi
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of jeharmse
> Sent: Friday, March 08, 2013 7:41 PM
> To: r-help@r-project.org
> Subject: Re: [R] Re move row.names column in dataframe
>
>
>
... the row.names will not interfere with any merging operation ...
Row names do not interfere with merge, but they cause other problems. In the
example, I want to test whether rows have the same entries (in some or all
columns). identical fails because of the row names, and all( == ) can fail
if
It works!
The rationale, if I have understood well, is to take my vector of N elements,
ask to remove the first/last element, and replace the blank space with a given
value.
Thank you all for the support!
-Original Message-
From: Duncan Murdoch
Date: Mon, 07 Jan 2013 13:16:50
To:
Cc:
Hello,
[ Sorry, I sent the last email as HTML, this time it's in plain text ]
Suppose my variable,S, (time for something to start) is a skew-normal
distribution [1]. Can glm and mgcv handle this type of distribution for the
dependent variable?
Regards
Saptarshi
[1] http://azzalini.stat.unipd.it/S
Hello,
Why don't you keep it on the list? I'm Ccing R Help.
If you put print statements just before the any(),
print(ind.c)
print(ind.r)
print(ind.sgn)
you'll see that all values are FALSE. So the problem is _not_ with
any(). You must look somewhere else on the function.
Hope this helps,
Thanks for the head-up Don.
Regards,
Phil
--
View this message in context:
http://r.789695.n4.nabble.com/Re-projecting-geotiff-tp4646616p4646736.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
https
r-sig-geo would be a better place to ask this question.
-Don
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 10/18/12 6:52 AM, "Filoche" wrote:
>Dear R users,
>
>I'm currently trying to re-project a geotiff in another coord
Dear R users,
I'm currently trying to re-project a geotiff in another coordinate system.
For instance, I have a tif image in UTM 19 zone which I would like to
reproject into UTM 18. I was wondering if it was possible in R.
Furthermore, I looked into 'rgdal' package, but I can't really find out if
Dear Luigi,
Here's an option:
boxplot(x, boxcol="white", whiskcol="white",medcol="white",staplecol="white")
abline(h=c(-1,0,1))
grid(NA, 4, lwd = 2)
boxplot(x,add=T)
Regards,
José Iparraguirre
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org
Hello,
Inline.
Em 07-08-2012 19:56, Abraham Mathew escreveu:
I have a data frame with a column of values that I want to bucket (group)
into specific levels.
str(dat)'data.frame': 3678 obs. of 39 variables:
$ id : int 23 76 129 156 166 180 200 214 296 344 ...
43-4352
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Abraham Mathew
> Sent: Tuesday, August 07, 2012 1:57 PM
> To: r-help@r-project.org
> Subject: [R] Re-grouping data in R
>
> I have a data frame with
I have a data frame with a column of values that I want to bucket (group)
into specific levels.
> str(dat)'data.frame': 3678 obs. of 39 variables:
$ id : int 23 76 129 156 166 180 200 214 296 344 ...
$ final_purchase_amount : Factor w/ 32 levels
"\\N","1082","110
Hi Bert,
The version of Matrix that ships with base worked for me. The cran
version of Matrix was the problem. To get it working I reinstalled R and
did NOT update Matrix.
Thanks to the package developers for their quick help on this one.
Regards,
Dr Robert Musk
Senior Forest Biometrici
Hi Bert,
The version of Matrix that ships with base worked for me. The cran
version of Matrix was the problem. To get it working I reinstalled R and
did NOT update Matrix.
Regards,
Dr Robert Musk
Senior Forest Biometrician
Management Research
Forestry Tasmania
79 Melville St Hobart Austr
?":::"
-- Bert
On Mon, Jul 9, 2012 at 10:45 AM, Niels2 wrote:
> Hallo Rob,
>
> have you figured out a solution to the error? I've got the same problem.
>
> regards
> N.
>
> --
> View this message in context:
> http://r.789695.n4.nabble.com/Matrix-package-loading-problem-Error-object-kronecker-i
Hallo Rob,
have you figured out a solution to the error? I've got the same problem.
regards
N.
--
View this message in context:
http://r.789695.n4.nabble.com/Matrix-package-loading-problem-Error-object-kronecker-is-not-exported-by-namespace-methods-tp4632861p4635878.html
Sent from the R help m
Dear R User's,
Thank you, Mark. The following code suggested by you worked for me.
dbGetQuery(connAE1, sprintf("INSERT INTO test1 (id) VALUES ( %d
);", i))
But I have a issue in passing "date and time data" as variable.If I
hard code the value like bellow it workings.
d
Sorry, but I have no idea then. I run it on a win64, without error message.
Best Regards.
- Mail original -
De : RobMusk
À : r-help@r-project.org
Cc :
Envoyé le : Dimanche 10 juin 2012 8h56
Objet : Re: [R] Re : Matrix package loading problem "Error : object
‘kronecker’ i
Hello,
Try 'SuppDists' package.
Best Regards
ps: it took less than 2 minutes for me by using a web search engine..
- Mail original -
De : shirin nezampour
À : "r-help@r-project.org"
Cc :
Envoyé le : Lundi 11 juin 2012 1h37
Objet : [R] generating random samples of IG distribution
Thanks Pascal, but all my packages are current. That is not the problem.
Regards,
--
View this message in context:
http://r.789695.n4.nabble.com/Matrix-package-loading-problem-Error-object-kronecker-is-not-exported-by-namespace-methods-tp4632861p4632911.html
Sent from the R help mailing list arc
Hello,
It is not an R issue but a Linux issue. Please check you have tcl/tk installed
on your system.
Best Regards,
Pascal
- Mail original -
De : John
À : r-help@r-project.org
Cc :
Envoyé le : Samedi 9 juin 2012 18h36
Objet : [R] Error when attempting to install tkrplot
I am getting
Hello,
Did you upgrade your R version from a previous one to the current one? If yes,
probably you should use:
> update.packages(checkBuilt=TRUE).
Best Regards,
Pascal
- Mail original -
De : RobMusk
À : r-help@r-project.org
Cc :
Envoyé le : Samedi 9 juin 2012 9h52
Objet : [R] Matri
Of course, if you have data points at hand.
Thanks Bert, for pointing out.
Ozgur
--
View this message in context:
http://r.789695.n4.nabble.com/Re-creating-distributions-tp4632739p4632849.html
Sent from the R help mailing list archive at Nabble.com.
Dear Andras,
A possible option might be checking the fit of your data to a specific
distribution and generating the data from the distribution to which your
data fit, with the parameters such as the MLE of them obtained by using the
avaiable data.
For instance, you can check whether your data is
probably way
>> over my head. I was wondering if you could point me into the right direction
>> using R to "re-build" the distribution that has the following parameters:
>>
>> mean: 0.007, median: 0.003, SD:0.011.
>>
>> I greatly apreciate your help,
&g
Hello Martin,
Did you try with 'polar.plot' from the 'plotrix' package?
Best Regards,
Pascal
- Mail original -
De : MartinD
À : r-help@r-project.org
Cc :
Envoyé le : Vendredi 8 juin 2012 18h01
Objet : [R] Rose plot (like a windrose)
Dear R Gurus,
I spent some time in looking for hel
Related comment:
"Even the data aren't sufficient." -- Brian Joiner (some years ago).
Explanation: See W.E. Deming on "analytic" vs "enumerative" statistics.
--- Bert
On Thu, Jun 7, 2012 at 8:06 PM, R. Michael Weylandt
wrote:
> Short answer: no, those are (in general) insufficient parameters t
Short answer: no, those are (in general) insufficient parameters to
characterize a distribution.
Long answer: unfortunately, it's not uncommon that those "summary
statistics" are the only ones reported based on someone or other's
limited experience with the Gaussian. There are a few things you cou
1 - 100 of 986 matches
Mail list logo
