Consider using a 'list' instead of creating a lot of objects that you then
have to manage:
x <- lapply(1:length(stats$hour), function(.indx) dataset[.indx, 3:15])
You can then access the data as x[[1]], ...
On Tue, May 20, 2008 at 12:58 PM, Douglas M. Hultstrand <
[EMAIL PROTECTED]> wrote:
> He
Take a look at ?assign
Juan Manuel Barreneche wrote:
I had to do the same thing many times, i usually use a combination of the
functions "eval", "parse" and "sprinf", as below:
k <- 1
for (i in 1:length(stats$hour)) {
eval(parse(text=sprintf("x%s <- dataset[%s,(3:15)]", i, k)))
k <- k+1
I had to do the same thing many times, i usually use a combination of the
functions "eval", "parse" and "sprinf", as below:
k <- 1
for (i in 1:length(stats$hour)) {
eval(parse(text=sprintf("x%s <- dataset[%s,(3:15)]", i, k)))
k <- k+1
}
what it does is:
eval(parse(text=STRING)) is a way to
Douglas -
To answer your question directly, use perhaps combination of ?assign and
?paste.
In general, you usually do not have to do this sort of thing, but can
use one of the apply family of functions (apply, sapply, lapply, mapply)
to do whatever you want with shorter, cleaner code and few
Hello,
I am trying to assign a variable name (x1,x2,x3...) in a loop statement
that is based on a counter (counter is based on the number of hours
within the datafile). The x1,x2 data will later be called for plotting
the data. Below is a clip of the for loop I am using, any suggestions?
k
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