Try this:
riskFactors <- c("A", "B", "C")
table(file[[riskFactor[1]]])
in a loop
for (i in riskFactor) table(file[[riskFactor[i]]])
On Mon, Jun 9, 2008 at 10:44 AM, EVANS David-William <
[EMAIL PROTECTED]> wrote:
> Hello all,
>
>
>
> After some months doing ok with R, I am embarrassed that I h
I have to say it is not clear at all what you expected. risk.factors
[1] is the character vector "file$A". You ask it to do a paste of
that, so of course it will just return itself. Then you do a table,
and naturally it tells you that it found "file$A" exactly once.
So what you have forgotte
Hello all,
After some months doing ok with R, I am embarrassed that I have to make
this my first posting to the help list. I am trying to run the
following (actually in a loop but shortened for the post):
risk.factors <- c("file$A", "file$B", "file$C", "file$D", "file$E")
table(pas
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