On Thu, 24 Feb 2022 13:31:09 -0500
Paul Bernal wrote:
> Basically, what I am being asked to do is to take the
> train.csv dataset, and store it in a data structure so that the data
> can be reshaped into a matrix of size 28 x 28, then I just need to
> print some indices of that (e.g. index 1, 2,
Thank you Ivan. Basically, what I am being asked to do is to take the
train.csv dataset, and store it in a data structure so that the data can be
reshaped into a matrix of size 28 x 28, then I just need to print some
indices of that (e.g. index 1, 2, 4, 7,, etc.)
I basically tried the following:
d
Dear Ivan, this is what I did:
dataframe_train <- as.matrix((read.csv(file_path_2, header=TRUE,
stringsAsFactors = FALSE)))
dim(dataframe_train) <- c(28,28)
The file I read was the one I attached in the first email. Would this do
the work to reshape original dataset into a 28 x 28 matrix? When I p
Hi Paul,
I may be missing something, but you can transform a vector to a matrix
of any desired size by using matrix().
For more nuanced processing of images, you might look into one of the
many image processing packages in R, or even the raster package (or
the newer terra).
Sarah
On Thu, Feb 24
On Thu, 24 Feb 2022 11:00:08 -0500
Paul Bernal wrote:
> Each pixel column in the training set has a name like pixel x, where
> x is an integer between 0 and 783, inclusive. To locate this pixel on
> the image, suppose that we have decomposed x as x = i ∗ 28 + j, where
> i and j are integers betwe
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