Re: [R] Percentile rank for each element in list

2010-09-07 Thread Peng, C
It seems to produce some strange values: > xx=1:10 > which(xx==quantile(x,0.2,type=3)) [1] 5 > which(xx==quantile(x,0.5,type=3)) integer(0) -- View this message in context: http://r.789695.n4.nabble.com/Percentile-rank-for-each-element-in-list-tp2529523p2530060.html Sent from the R help mailin

Re: [R] Percentile rank for each element in list

2010-09-07 Thread Arun.stat
Otherwise you can try following: x <- c(1,5,100,300,250,200,550,900,1000) which(x==quantile(x,0.25,type=3)) This will always return number within your vector. See further information with ?'quantile' Thanks and regards, -- View this message in context: http://r.789695.n4.nabble.com/Percentil

Re: [R] Percentile rank for each element in list

2010-09-07 Thread Peng, C
Is this what you want to have: > x <- c(1,5,100,300,250,200,550,900,1000) > # assume you want the position of 25th percentile > which(x==quantile(x,0.25)) [1] 3 Note that "position" is meaningful only when the percentile is one of the observed data values. If you want to know the "position" of

Re: [R] Percentile rank for each element in list

2010-09-07 Thread Ista Zahn
Hi, I think you want ecdf(), but read the help page because it works a little different than you might expect. ecdf.x <- ecdf(x) ecdf.x(x) Best, Ista On Tue, Sep 7, 2010 at 8:37 AM, mic wrote: > Hlp > > Given this data >  x <- c(1,5,100,300,250,200,550,900,1000) >> quantile(x) >  0%  25%  5

[R] Percentile rank for each element in list

2010-09-07 Thread mic
Hlp Given this data x <- c(1,5,100,300,250,200,550,900,1000) > quantile(x) 0% 25% 50% 75% 100% 1 100 250 550 1000 When I run the quantile, I can only know the value of the nth percentile I want to know what's the percentile position of each items in the list Sample 1 = 100% on th