Hi, Gabor
Yes, I am familiar with tail() function. I use it extensively on a day
to day basis.
In this particular case I needed to order a zoo object by date, after
I have created it with RBloomberg.
Thank you for your time!
Regards,
Sergey
On Thu, Jul 9, 2009 at 14:36, Gabor Grothendieck wrote
One additional thought. If the reason you want to do that is
just so that you can see the last few rows more easily then
tail(Data)
will display the last few rows or tail(Data, 10) will display
the last 10 rows.
On Thu, Jul 9, 2009 at 7:36 AM, Sergey Goriatchev wrote:
> Hi, Gabor
>
> Thank you!
Hi, Gabor
Thank you!
That is exactly what I did, even before your email. :-)
Regards,
Sergey
On Thu, Jul 9, 2009 at 12:52, Gabor Grothendieck wrote:
> To display that object in reverse time order try this:
>
> as.data.frame(Data)[nrow(Data):1, ]
>
>
> On Thu, Jul 9, 2009 at 5:21 AM, Sergey Goria
To display that object in reverse time order try this:
as.data.frame(Data)[nrow(Data):1, ]
On Thu, Jul 9, 2009 at 5:21 AM, Sergey Goriatchev wrote:
> Hello everyone,
>
> Say I have zoo object
>
> x.Date <- as.Date("2003-02-01") + c(1, 3, 7, 9, 14) - 1
> x <- zoo(rnorm(5), x.Date)
> y <- zoo(rt(5
Hello everyone,
Say I have zoo object
x.Date <- as.Date("2003-02-01") + c(1, 3, 7, 9, 14) - 1
x <- zoo(rnorm(5), x.Date)
y <- zoo(rt(5, df=2), x.Date)
z <- zoo(rt(5, df=5), x.Date)
Data <- merge(x,y,z)
What should I do to make the latest values appear at the top?
Thank you for your help!
Rega
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