Re: [R] Ordering zoo-object by its index

2009-07-09 Thread Sergey Goriatchev
Hi, Gabor Yes, I am familiar with tail() function. I use it extensively on a day to day basis. In this particular case I needed to order a zoo object by date, after I have created it with RBloomberg. Thank you for your time! Regards, Sergey On Thu, Jul 9, 2009 at 14:36, Gabor Grothendieck wrote

Re: [R] Ordering zoo-object by its index

2009-07-09 Thread Gabor Grothendieck
One additional thought. If the reason you want to do that is just so that you can see the last few rows more easily then tail(Data) will display the last few rows or tail(Data, 10) will display the last 10 rows. On Thu, Jul 9, 2009 at 7:36 AM, Sergey Goriatchev wrote: > Hi, Gabor > > Thank you!

Re: [R] Ordering zoo-object by its index

2009-07-09 Thread Sergey Goriatchev
Hi, Gabor Thank you! That is exactly what I did, even before your email. :-) Regards, Sergey On Thu, Jul 9, 2009 at 12:52, Gabor Grothendieck wrote: > To display that object in reverse time order try this: > > as.data.frame(Data)[nrow(Data):1, ] > > > On Thu, Jul 9, 2009 at 5:21 AM, Sergey Goria

Re: [R] Ordering zoo-object by its index

2009-07-09 Thread Gabor Grothendieck
To display that object in reverse time order try this: as.data.frame(Data)[nrow(Data):1, ] On Thu, Jul 9, 2009 at 5:21 AM, Sergey Goriatchev wrote: > Hello everyone, > > Say I have zoo object > > x.Date <- as.Date("2003-02-01") + c(1, 3, 7, 9, 14) - 1 > x <- zoo(rnorm(5), x.Date) > y <- zoo(rt(5

[R] Ordering zoo-object by its index

2009-07-09 Thread Sergey Goriatchev
Hello everyone, Say I have zoo object x.Date <- as.Date("2003-02-01") + c(1, 3, 7, 9, 14) - 1 x <- zoo(rnorm(5), x.Date) y <- zoo(rt(5, df=2), x.Date) z <- zoo(rt(5, df=5), x.Date) Data <- merge(x,y,z) What should I do to make the latest values appear at the top? Thank you for your help! Rega