Greg Snow wrote:
> Here is another approach using transform and ave which I think is a
> little simpler than the others suggested:
>
>
>> new.data <- transform( iris,
>>
> + normSW = Sepal.Width / ave(Sepal.Width, Species, FUN=max),
> + normSL = Sepal.Length / ave(Sepal.Length, Species
r 09, 2007 3:57 AM
> To: r-help@r-project.org
> Subject: [R] Normalizing grouped data in a data frame
>
> Hi
> I am a newbie to R but have tried a number of ways in R to do
> this and can't find a good solution. (I could do it out of R
> in perl or awk but would like
On 11/9/2007 10:22 AM, Sandy Small wrote:
> Thank you very much.
> That works nicely.
> The trick I particularly needed was "within"which I didn't know about.
within() is new in 2.6.0; it's a nice addition. There's also
transform() which could be used in this situation, replacing
within(subset,
Thank you very much.
That works nicely.
The trick I particularly needed was "within"which I didn't know about.
Also nice to get a data frame out with "sparseby" instead of just a
mulit-array with "by"
Sandy
Duncan Murdoch wrote:
> Sandy Small wrote:
>> Hi
>> I am a newbie to R but have tried a nu
On Nov 9, 2007 5:56 AM, Sandy Small <[EMAIL PROTECTED]> wrote:
> Hi
> I am a newbie to R but have tried a number of ways in R to do this and
> can't find a good solution. (I could do it out of R in perl or awk but
> would like to know how to do this in R).
>
> I have a large data frame 49 variables
Sandy Small wrote:
> Hi
> I am a newbie to R but have tried a number of ways in R to do this and
> can't find a good solution. (I could do it out of R in perl or awk but
> would like to know how to do this in R).
>
> I have a large data frame 49 variables and 7000 observations however for
> simp
Hi
I am a newbie to R but have tried a number of ways in R to do this and
can't find a good solution. (I could do it out of R in perl or awk but
would like to know how to do this in R).
I have a large data frame 49 variables and 7000 observations however for
simplicity I can express it in the f
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