On Mon, Apr 23, 2012 at 02:33:22PM -0700, cyclondude wrote:
> Yes. That is what I was looking for. Is there a simple way to (in this
> scenario)
>
>
> > out[[1]]
>
> v1 v2
> 1 a 1
> 4 a 2
> 7 a 3
>
> > a <- out[[1]]
>
> for each one?
Hi.
If you want to generate variable nam
There are, but it's generally considered better style to keep them all
in a single list and use lapply() if you want to do things to each
element.
Michael
On Mon, Apr 23, 2012 at 5:33 PM, cyclondude wrote:
> Yes. That is what I was looking for. Is there a simple way to (in this
> scenario)
>
>
Yes. That is what I was looking for. Is there a simple way to (in this
scenario)
> out[[1]]
v1 v2
1 a 1
4 a 2
7 a 3
> a <- out[[1]]
for each one?
Thanks!
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http://r.789695.n4.nabble.com/Newbie-Question-on-making-subsets-for-every-element-of-a
On Mon, Apr 23, 2012 at 10:58:26AM -0700, cyclondude wrote:
> Hello, very new to R, playing with tables, and I am trying to do
>
> x <- subset(data, columnlabel == x)
>
> for every element in my column that I could find by using
>
> table (data [,"columnlabel"])
Hi.
The following may be clos
Hello, very new to R, playing with tables, and I am trying to do
x <- subset(data, columnlabel == x)
for every element in my column that I could find by using
table (data [,"columnlabel"])
I'd appreciate any useful help and I'm sorry if I didn't get the terminology
perfect. Thanks.
--
Vie
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