> The code I've attached works for a population of 400 and samples 100 times.
> I'd like to extend this to 300 samples and 3 populations. So, the x-axis would
> range from 0-300 samples.
>
> What I'm having trouble with is finding a way to change the population mid-
> way through the function. I w
Hi Caitlin and Ben,
Thanks for your responses! My issue is that I'd like to create one
continuous line, rather than 3 lines overlayed.
The code I've attached works for a population of 400 and samples 100 times.
I'd like to extend this to 300 samples and 3 populations. So, the x-axis
would range f
Hmmm.
If I understand you correctly, your question has to do with adding lines to
your graph? If so, my ggplot2 skills are sort of floppy, but you could append
your sampling results to your data frame (one for each sample set) and then
simply add layers. Sort of like this.
N <- 10
x <- 1:N
d
Hi Ben,
That's exactly right! Except for each set it's the sample population that
is 400, 800 or 300. I want to take 3 samples, each of 100, where only the
population differs. I can do this separately, but I'm having trouble
putting them all on the same graph.
I'd like to have sample on the x axi
Hi Kirsten,
I can run your example code but I can't quite follow your division of sampling.
Can you restate the the task? Below is what I think you are asking for, but I
have the feeling I may be off the mark.
Set A: 400 samples, draw 100 in range of 5 to 15
Set B: 800 samples, draw 100 in
Hi! Thanks for taking the time to read this.
The code below creates a graph that takes 100 samples that are between 5%
and 15% of the population (400).
What I'd like to do, however, is add two other sections to the graph. It
would look something like this:
from 1-100 samples take 100 samples tha
Thank you Jeff. Your idea, as i mentioned on my previous posting, did
indeed work. I read somewhere that both data table dplyr do great many
things and i plan to learn both as much as i can. Suggestions on this list
either get you the answer you are looking for or give you lead to an answer.
Thank
)
A B C D E F
3 1 1 0 1 1
It is probably preferable to obtain logical vectors for Num and Day before
starting tabulation.
Cheers
Petr
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Ek Esawi
> Sent: Wednesday, May 3, 2017 5:17 PM
> To: r-help
You seem to be unaware of the "aggregate" data processing concept. There are
many ways to accomplish aggregation, but I am not fluent in data.table methods
but knowing the concept is the first step.
Perhaps look closely at [1], or Google for data table aggregation yourself?
[1]
https://www.r-
Thank you both Boris and Jim. Thank you, Boris, for advising to read the
posting guide; I had and I just did.
Jim’s idea is exactly what I want; however, I could not pass sset1, sset2,
etc. to the j nested loop and collect the results in an vector.
Here attached my code, file, and my question whi
Hi Ek,
I think you want your example to look like this:
Sample<-read.table(text=
"Num Color Grade Value Month Day
1 yellow A 20 May 1
2 green B 25 June 2
3 green A 10 April 3
4 black A 17 August 3
5 red C 5 December 5
6 orange D 0 January 13
7 orange E 12 January 5
8 orange F 11 February 8
9 orang
There's a lot that doesn't make sense here. I think what you need to do is
produce a small, reproducible example, post that with dput() and state your
question more clearly - including what you have tried and what didn't work.
You'll probably be amazed how quickly you will get good advice if
_y
I have a huge data file; a sample is listed below. I am using the package
data table to process the file and I am stuck on one issue and need some
feedback. I used fread to create a data table. Then I divided the data
table (named File1) into 10 general subsets using common table commands
such as:
pick.a[count],pick.d[count1]))
tc1=sum(t.control(m.control,pick.a[count]))
output=c(output,ts1/tc1)
}
}
m1=matrix(output,200,100)
print(m1)
From: arun
Sent: Saturday, January 11, 2014 6:00 PM
To: Mathew Nagendran
Subject: Re: [R] Nested for loo
Hi,
I guess you need to replace t() with t.control() or t.sham()
output <-vector()
for(count in 1:length(pick.a)){
for(count1 in 1:length(pick.d)){
ts1 = sum(t.sham(m.sham,pick.a[count],pick.d[count1]))
tc1 <- sum(t.control(m.control,pick.a[count]))
output= c(output,ts1/tc1)
}
}
m1 <- matri
r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf
> Of Mathew Nagendran
> Sent: Saturday, January 11, 2014 10:46 AM
> To: r-help@r-project.org
> Subject: [R] Nested for loop help please.
>
> Hi all I am relatively new to R. I am trying to crea
Hello,
You are using the function ?t(), matrix transpose, with more than one
argument. What is that supposed to do? The error message says that the
other two arguments are not used (because they are illegal). And you
don't need to transpose a vector to sum its components.
Hope this helps,
R
Hi all I am relatively new to R. I am trying to create a nested for loop but i
keep getting an error message (unused argument). Can someone help me find out
where I am goign wrong?
> m.control=c(1.45,9.40,9.96,4.2,1.86,0.2)
> m.sham=c(3.39,23.94,23.62,10.08,2.99,1.09)
>
> t.control=function(m, a
> - Original Message -
> From: arun.gurubaramurugeshan
> To: r-help@r-project.org
> Cc:
> Sent: Thursday, June 28, 2012 5:03 PM
> Subject: [R] Nested For Loop
>
> I am creating a nested for loop and following are the codes I'm using, but I
> am not
s one line is the shortest
A.K.
- Original Message -
From: arun.gurubaramurugeshan
To: r-help@r-project.org
Cc:
Sent: Thursday, June 28, 2012 5:03 PM
Subject: [R] Nested For Loop
I am creating a nested for loop and following are the codes I'm using, but I
am not acheiving wh
On Jun 28, 2012, at 5:03 PM, arun.gurubaramurugeshan wrote:
I am creating a nested for loop and following are the codes I'm
using, but I
am not acheiving what I want.
I have a vector
d<-151:159
I have another vector
e<-e<-c("apple", "orange", "banana")
I need to create f as
151apple
1
reversed them, Should be:
levels(interaction(d,e,sep="")
>
> of course.
-- Bert
On Fri, Jun 29, 2012 at 2:46 AM, Bert Gunter wrote:
> ... or even simpler:
>
> levels(interaction(e,d,sep=""))
>
> ... and PLEASE read "An Introduction to R" before further posting to learn
> how to program in R r
... or even simpler:
levels(interaction(e,d,sep=""))
... and PLEASE read "An Introduction to R" before further posting to learn
how to program in R rather than trying to fit what you do in other
languages to R.
Cheers,
Bert
On Fri, Jun 29, 2012 at 12:48 AM, Rui Barradas wrote:
> Hello,
>
> Tr
Hello,
Try, in one line and no loops, surely not nested,
apply(rev(expand.grid(e, d, stringsAsFactors = FALSE)), 1, paste,
collapse="")
Hope this helps,
Rui Barradas
Em 28-06-2012 22:03, arun.gurubaramurugeshan escreveu:
I am creating a nested for loop and following are the codes I'm using
I am creating a nested for loop and following are the codes I'm using, but I
am not acheiving what I want.
I have a vector
d<-151:159
I have another vector
e<-e<-c("apple", "orange", "banana")
I need to create f as
151apple
151orange
151banana
.
.
159apple
159orange
159banana
Here is how I w
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