Thank you Karim,
I'll try that.
Thanks!
Raff
Sent from my iPhone
> On Dec 10, 2014, at 1:48 PM, "Karim Mezhoud" wrote:
>
> Hi,
> Could you try rbind.na.R function.
> karim
>
> Ô__
> c/ /'_;kmezhoud
> (*) \(*) ⴽⴰⵔⵉⵎ ⵎⴻⵣⵀⵓⴷ
> http://bioinformatics.tn/
>
>
>
>> On Wed, Dec 10, 2014
Hi,
Could you try rbind.na.R function.
karim
Ô__
c/ /'_;kmezhoud
(*) \(*) ⴽⴰⵔⵉⵎ ⵎⴻⵣⵀⵓⴷ
http://bioinformatics.tn/
On Wed, Dec 10, 2014 at 10:34 PM, Raffaello Vardavas wrote:
> Dear All,
>
> I have a data fame. Each column has numerical values but some columns may
> have NA values.
>
Dear All,
I have a data fame. Each column has numerical values but some columns may have
NA values.
I'd like a table showing the summary statistics for each column. This is what I
do:
I first do the following:
apply(df[,metrics],2,summary,na.rm=T)
giving:
$degree
Min. 1st Qu. MedianM
On Sep 21, 2010, at 11:28 , Jeff Newmiller wrote:
> Short answer: don't do that.
>
> The format function is for preparing data for output. Do your data
> manipulations on a data frame you keep for such use, and only use format to
> prepare for output.
But isn't that what the OP is doing? It i
On Sep 21, 2010, at 5:28 AM, Jeff Newmiller wrote:
Short answer: don't do that.
The format function is for preparing data for output. Do your data
manipulations on a data frame you keep for such use, and only use
format to prepare for output.
That is excellent advice. But to answer the q
Short answer: don't do that.
The format function is for preparing data for output. Do your data
manipulations on a data frame you keep for such use, and only use format to
prepare for output.
"n.via...@libero.it" wrote:
>Dear R list
>I have a problem with NA, which should be a string, but R s
Dear R list
I have a problem with NA, which should be a string, but R seems that it
doesn't recognize it. What I do is first give the format command to my data
frame:
format.data.frame(mydata,big.mark=" ")
so I give a blank as thousand separator. All my records in my data frame
become strings
Thank you very much, Dr. Ripley. The solution "ifelse()" you provided
is exactly what I want. I am so happy this morning for that I recieved
your email. Yesterday night I was trying to write a loop to substitute
NA. But now I learn that "ifelse()" does a much more efficient work.
Really appreciate
On Wed, 16 Apr 2008, Lu, Jiang wrote:
> Dear R helpers,
>
> I was doing a genetic project with two datasets X and Y. There are
> some IDs in both data sets, and others in either data set. I used
> "merge(x,y,by="ID",all=TRUE)". The data set Y contains a variable (a
> genotype) which is also in dat
Dear R helpers,
I was doing a genetic project with two datasets X and Y. There are
some IDs in both data sets, and others in either data set. I used
"merge(x,y,by="ID",all=TRUE)". The data set Y contains a variable (a
genotype) which is also in data X. When I merge X with Y, these two
variables we
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