How about:
d_sample_1 <- floor(d_sample/100) * 100
for (i in 1:nrow(d_sample_1)) {
d_sample_1[i, duplicated(unlist(d_sample_1[i, ]))] <- NA
}
B.
> On Apr 25, 2017, at 1:10 PM, Bert Gunter wrote:
>
> If I understand you correctly, one way is:
>
>> z <- rep(LETTERS[1:3],4)
>> z
> [1] "A
If I understand you correctly, one way is:
> z <- rep(LETTERS[1:3],4)
> z
[1] "A" "B" "C" "A" "B" "C" "A" "B" "C" "A" "B" "C"
> z[!duplicated(z)]
[1] "A" "B" "C"
?duplicated
-- Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it
Hi All,
in my current project I am working with multiple-response questions
(MRSets):
-- Coding --
100 Main Code 1
110 Sub Code 1.1
120 Sub Code 1.2
130 Sub Code 1.3
200 Main Code 2
210 Sub Code 2.1
220 Sub Code 2.2
230 Sub Code 2.3
300 Main Code 3
310 Sub Code 3.1
320 Sub Code 3.2
The coding
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